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(3y+2)/(4y^2+y)+(y-3)/(16y^2-1)=3/(4y-1) equation

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Numerical solution:

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The solution

You have entered [src]
3*y + 2      y - 3        3   
-------- + --------- = -------
   2           2       4*y - 1
4*y  + y   16*y  - 1          
$$\frac{y - 3}{16 y^{2} - 1} + \frac{3 y + 2}{4 y^{2} + y} = \frac{3}{4 y - 1}$$
The graph
Sum and product of roots [src]
sum
-1 + 2
$$-1 + 2$$
=
1
$$1$$
product
-2
$$- 2$$
=
-2
$$-2$$
-2
Rapid solution [src]
y1 = -1
$$y_{1} = -1$$
y2 = 2
$$y_{2} = 2$$
y2 = 2
Numerical answer [src]
y1 = -1.0
y2 = 2.0
y2 = 2.0