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How to use it?
- Equation:
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Equation 1-7*(4+2*x)=-9-4*x
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Equation sin(x)=2
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Equation -x-2+3(x-3)=3(4-x)-3
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Equation (x-2)^2+(x-3)^2=2x^2
- Express {x} in terms of y where:
- 17*x-18*y=10
- -12*x-3*y=-9
- -6*x-2*y=-10
- 18*x+14*y=-11
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Identical expressions
- one - seven *(four + two *x)=- nine - four *x
- 1 minus 7 multiply by (4 plus 2 multiply by x) equally minus 9 minus 4 multiply by x
- one minus seven multiply by (four plus two multiply by x) equally minus nine minus four multiply by x
- 1-7(4+2x)=-9-4x
- 1-74+2x=-9-4x
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Similar expressions
- 1-7*(4+2x)=-9-4x
- 1-7*(4+2*x)=-9+4*x
- 0,5(8x+1)=15-(9-4x)
- 1-7*(4-2*x)=-9-4*x
- 1-7*(4+2*x)=-9-4x
- -9-4x+12=0
- 1-7*(4+2*x)=+9-4*x
- 1+7*(4+2*x)=-9-4*x
1-7*(4+2*x)=-9-4*x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- 14 x = 18 - 4 x$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-10\right) x = 18$$
Divide both parts of the equation by -10
We get the answer: x = -9/5
1-7*(4+2*x) = -9-4*x
Expand brackets in the left part
1-7*4-7*2*x = -9-4*x
Looking for similar summands in the left part:
-27 - 14*x = -9-4*x
Move free summands (without x)
from left part to right part, we given:
$$- 14 x = 18 - 4 x$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-10\right) x = 18$$
Divide both parts of the equation by -10
x = 18 / (-10)
We get the answer: x = -9/5
Sum and product of roots
[src]
sum
-9/5
$$- \frac{9}{5}$$
=
-9/5
$$- \frac{9}{5}$$
product
-9/5
$$- \frac{9}{5}$$
=
-9/5
$$- \frac{9}{5}$$
-9/5
The graph