Mister Exam
Other calculators
-
How to use it?
- Express {x} in terms of y where:
- -6*x-2*y=-10
- 18*x+14*y=-11
- -8*x-12*y=15
- sin(xy)+cos(xy)=tg(x+y)
- Equation:
-
Equation 1-7*(4+2*x)=-9-4*x
-
Equation sin(x)=2
-
Equation -x-2+3(x-3)=3(4-x)-3
-
Equation 4x=24+x
- Limit of the function:
-
-10
- -10
-
Identical expressions
- - six *x- two *y=- ten
- minus 6 multiply by x minus 2 multiply by y equally minus 10
- minus six multiply by x minus two multiply by y equally minus ten
- -6x-2y=-10
-
Similar expressions
- -6*x+2*y=-10
- -6*x-2*y=+10
- 6*x-2*y=-10
Express x in terms of y where -6*x-2*y=-10
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 6 x = 2 y - 10$$
Divide both parts of the equation by -6
We get the answer: x = 5/3 - y/3
-6*x-2*y = -10
Looking for similar summands in the left part:
-6*x - 2*y = -10
Move the summands with the other variables
from left part to right part, we given:
$$- 6 x = 2 y - 10$$
Divide both parts of the equation by -6
x = -10 + 2*y / (-6)
We get the answer: x = 5/3 - y/3
Rapid solution
[src]
5 re(y) I*im(y)
x1 = - - ----- - -------
3 3 3
$$x_{1} = - \frac{\operatorname{re}{\left(y\right)}}{3} - \frac{i \operatorname{im}{\left(y\right)}}{3} + \frac{5}{3}$$
x1 = -re(y)/3 - i*im(y)/3 + 5/3