Mister Exam
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How to use it?
- Equation:
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Equation (x+6)^3=25*(x+6)
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Equation 1-5x=-6x+8
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Equation 1-5*x=-6*x+8
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Equation (x-2)^2=(x-9)^2
- Express {x} in terms of y where:
- -7*x-7*y=-14
- 10*x-2*y=0
- -15*x+17*y=13
- -11*x-15*y=14
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Identical expressions
- eleven -5x= twelve -6x
- 11 minus 5x equally 12 minus 6x
- eleven minus 5x equally twelve minus 6x
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Similar expressions
- -11x1^2-6x2^2-6x3^2+12x1x2-102x1x3+6x2x3
- 2(7x+11)-5x=5x
- (8x-11)*(-5x+17)=0
- 11+5x=12-6x
- (x^2-7*x-11)-(5*x^2-13*x-18)=16-4*x^2
- 11-5x=12+6x
11-5x=12-6x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$- 5 x = - 6 x + 1$$
Move the summands with the unknown x
from the right part to the left part:
$$x = 1$$
We get the answer: x = 1
11-5*x = 12-6*x
Move free summands (without x)
from left part to right part, we given:
$$- 5 x = - 6 x + 1$$
Move the summands with the unknown x
from the right part to the left part:
$$x = 1$$
We get the answer: x = 1
Sum and product of roots
[src]
sum
1
$$\left(1\right)$$
=
1
$$1$$
product
1
$$\left(1\right)$$
=
1
$$1$$
The graph