Mister Exam
Other calculators
-
How to use it?
- Equation:
- Equation log3(x2–3x–5)=log3(7–2x)
-
Equation 836-16*m=420
-
Equation sin(x)=-2
-
Equation x⁴-3x²-4=0
- Express {x} in terms of y where:
- 60x^2y+75x^2y^2+120xy^260x2y+75x2y2+120xy2приx=-0,5x=−0,5,y=0,4y=0,4.
- (x-17)^2+(y+26)^2=16(x−17)2+(y+26)2=16.
- 5*x-5*y=20
- 8*x-7*y=-13
-
Identical expressions
- log3(x2–3x– five)=log3(seven –2x)
- logarithm of 3(x2–3x–5) equally logarithm of 3(7–2x)
- logarithm of 3(x2–3x– five) equally logarithm of 3(seven –2x)
- log3x2–3x–5=log37–2x
-
What you mean?
- log(x^2 - 3*x - 1*5)/log(3) = log(7 - 2*x)/log(3)
You entered:
log3(x2–3x–5)=log3(7–2x)
What you mean?
log3(x2–3x–5)=log3(7–2x) equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
log(x2 - 3*x - 5) log(7 - 2*x)
----------------- = ------------
log(3) log(3)
$$\frac{\log{\left(- 3 x + x_{2} - 5 \right)}}{\log{\left(3 \right)}} = \frac{\log{\left(7 - 2 x \right)}}{\log{\left(3 \right)}}$$
The graph
Sum and product of roots
[src]
sum
0 + -12 + x2
$$\left(x_{2} - 12\right) + 0$$
=
-12 + x2
$$x_{2} - 12$$
product
1*(-12 + x2)
$$1 \left(x_{2} - 12\right)$$
=
-12 + x2
$$x_{2} - 12$$
-12 + x2