Mister Exam
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How to use it?
- Equation:
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Equation sinx⋅tgx−(–√3)sinx=0
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Equation 4cosx+sin3x−8x=x^3+4
- Equation 1,6a²c*(-2ac²)
- Equation s-0,522s=3,585
- Express {x} in terms of y where:
- 5*x-5*y=20
- 8*x-7*y=-13
- 15*x-15*y=16
- 9*x+18*y=6
- Graphing y =:
- x^3+4
- Derivative of:
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x^3+4
- Factor polynomial:
- x^3+4
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Identical expressions
- four cosx+sin three x−8x=x^3+4
- 4 co sinus of e of x plus sinus of 3x−8x equally x cubed plus 4
- four co sinus of e of x plus sinus of three x−8x equally x cubed plus 4
- 4cosx+sin3x−8x=x3+4
- 4cosx+sin3x−8x=x³+4
- 4cosx+sin3x−8x=x to the power of 3+4
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Similar expressions
- 2x^3+4x^2-3x+6/4=0
- (x^3+4)/x^2=0
- 4cosx-sin3x−8x=x^3+4
- √(x^3+4x^2-36)=x
- 4cosx+sin3x−8x=x^3-4
4cosx+sin3x−8x=x^3+4 equation
The teacher will be very surprised to see your correct solution 😉
The solution
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3 4*cos(x) + sin(3*x) - 8*x = x + 4
$$- 8 x + \sin{\left(3 x \right)} + 4 \cos{\left(x \right)} = x^{3} + 4$$
The graph