1,6a²c*(-2ac²) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Vieta's Theorem
rewrite the equation
$$- 2 a c^{2} \frac{8 a^{2}}{5} c = 0$$
of
$$a c^{3} + b c^{2} + c^{2} + d = 0$$
as reduced cubic equation
$$c^{3} + \frac{b c^{2}}{a} + \frac{c^{2}}{a} + \frac{d}{a} = 0$$
$$c^{3} = 0$$
$$c^{3} + c^{2} p + c q + v = 0$$
where
$$p = \frac{b}{a}$$
$$p = 0$$
$$q = \frac{c}{a}$$
$$q = 0$$
$$v = \frac{d}{a}$$
$$v = 0$$
Vieta Formulas
$$c_{1} + c_{2} + c_{3} = - p$$
$$c_{1} c_{2} + c_{1} c_{3} + c_{2} c_{3} = q$$
$$c_{1} c_{2} c_{3} = v$$
$$c_{1} + c_{2} + c_{3} = 0$$
$$c_{1} c_{2} + c_{1} c_{3} + c_{2} c_{3} = 0$$
$$c_{1} c_{2} c_{3} = 0$$
Sum and product of roots
[src]
$$0$$
$$0$$
$$0$$
$$0$$