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18x-35+5*x^2=0 equation

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Numerical solution:

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The solution

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18*x - 35 + 5*x  = 0
$$5 x^{2} + 18 x - 35 = 0$$
Detail solution
This equation is of the form
$$a\ x^2 + b\ x + c = 0$$
A quadratic equation can be solved using the discriminant
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where $D = b^2 - 4 a c$ is the discriminant.
Because
$$a = 5$$
$$b = 18$$
$$c = -35$$
, then
$$D = b^2 - 4\ a\ c = $$
$$18^{2} - 5 \cdot 4 \left(-35\right) = 1024$$
Because D > 0, then the equation has two roots.
$$x_1 = \frac{(-b + \sqrt{D})}{2 a}$$
$$x_2 = \frac{(-b - \sqrt{D})}{2 a}$$
or
$$x_{1} = \frac{7}{5}$$
Simplify
$$x_{2} = -5$$
Simplify
Vieta's Theorem
rewrite the equation
$$5 x^{2} + 18 x - 35 = 0$$
of
$$a x^{2} + b x + c = 0$$
as reduced quadratic equation
$$x^{2} + \frac{b x}{a} + \frac{c}{a} = 0$$
$$x^{2} + \frac{18 x}{5} - 7 = 0$$
$$p x + x^{2} + q = 0$$
where
$$p = \frac{b}{a}$$
$$p = \frac{18}{5}$$
$$q = \frac{c}{a}$$
$$q = -7$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = - \frac{18}{5}$$
$$x_{1} x_{2} = -7$$
Sum and product of roots [src]
sum
-5 + 7/5
$$\left(-5\right) + \left(\frac{7}{5}\right)$$
=
-18/5
$$- \frac{18}{5}$$
product
-5 * 7/5
$$\left(-5\right) * \left(\frac{7}{5}\right)$$
=
-7
$$-7$$
Rapid solution [src]
x_1 = -5
$$x_{1} = -5$$
x_2 = 7/5
$$x_{2} = \frac{7}{5}$$
Numerical answer [src]
x1 = 1.4
x2 = -5.0
x2 = -5.0