2 sin (x)
sin(x)^2
Let u=sin(x)u = \sin{\left(x \right)}u=sin(x).
Apply the power rule: u2u^{2}u2 goes to 2u2 u2u
Then, apply the chain rule. Multiply by ddxsin(x)\frac{d}{d x} \sin{\left(x \right)}dxdsin(x):
The derivative of sine is cosine:
The result of the chain rule is:
Now simplify:
The answer is:
2*cos(x)*sin(x)
/ 2 2 \ 2*\cos (x) - sin (x)/
-8*cos(x)*sin(x)