5 sin (x)
d / 5 \ --\sin (x)/ dx
Let u=sin(x)u = \sin{\left(x \right)}u=sin(x).
Apply the power rule: u5u^{5}u5 goes to 5u45 u^{4}5u4
Then, apply the chain rule. Multiply by ddxsin(x)\frac{d}{d x} \sin{\left(x \right)}dxdsin(x):
The derivative of sine is cosine:
The result of the chain rule is:
The answer is:
4 5*sin (x)*cos(x)
3 / 2 2 \ 5*sin (x)*\- sin (x) + 4*cos (x)/
2 / 2 2 \ 5*sin (x)*\- 13*sin (x) + 12*cos (x)/*cos(x)