Derivative of log((x+3)/(x-3))

1. Let $u = \frac{x + 3}{x - 3}$.

2. The derivative of $\log{\left(u \right)}$ is $\frac{1}{u}$.

3. Then, apply the chain rule. Multiply by $\frac{d}{d x} \frac{x + 3}{x - 3}$:

   1. Apply the quotient rule, which is:

      $$\frac{d}{d x} \frac{f{\left(x \right)}}{g{\left(x \right)}} = \frac{- f{\left(x \right)} \frac{d}{d x} g{\left(x \right)} + g{\left(x \right)} \frac{d}{d x} f{\left(x \right)}}{g^{2}{\left(x \right)}}$$

      $f{\left(x \right)} = x + 3$ and $g{\left(x \right)} = x - 3$.

      To find $\frac{d}{d x} f{\left(x \right)}$:

      1. Differentiate $x + 3$ term by term:

         1. The derivative of the constant $3$ is zero.

         2. Apply the power rule: $x$ goes to $1$

         The result is: $1$

      To find $\frac{d}{d x} g{\left(x \right)}$:

      1. Differentiate $x - 3$ term by term:

         1. The derivative of the constant $-3$ is zero.

         2. Apply the power rule: $x$ goes to $1$

         The result is: $1$

      Now plug in to the quotient rule:

      $- \frac{6}{\left(x - 3\right)^{2}}$

   The result of the chain rule is:

   $$- \frac{6 \left(x - 3\right)}{\left(x - 3\right)^{2} \left(x + 3\right)}$$

4. Now simplify:

   $$- \frac{6}{x^{2} - 9}$$

The answer is: