Derivative of ln(sin2x)

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log(sin(2*x))

$$\log{\left(\sin{\left(2 x \right)} \right)}$$

d                
--(log(sin(2*x)))
dx

$$\frac{d}{d x} \log{\left(\sin{\left(2 x \right)} \right)}$$

Transform

Detail solution

Let $u = \sin{\left(2 x \right)}$ .
The derivative of $\log{\left(u \right)}$ is $\frac{1}{u}$ .
Then, apply the chain rule. Multiply by $\frac{d}{d x} \sin{\left(2 x \right)}$ :
1. Let $u = 2 x$ .
2. The derivative of sine is cosine:
  
  $\frac{d}{d u} \sin{\left(u \right)} = \cos{\left(u \right)}$
3. Then, apply the chain rule. Multiply by $\frac{d}{d x} 2 x$ :
  1. The derivative of a constant times a function is the constant times the derivative of the function.
    1. Apply the power rule: $x$ goes to $1$
    So, the result is: $2$
  The result of the chain rule is:
  
  $2 \cos{\left(2 x \right)}$
The result of the chain rule is:

$\frac{2 \cos{\left(2 x \right)}}{\sin{\left(2 x \right)}}$
Now simplify:

$\frac{2}{\tan{\left(2 x \right)}}$

The answer is:

$\frac{2}{\tan{\left(2 x \right)}}$

The graph

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The first derivative [src]

2*cos(2*x)
----------
 sin(2*x)

$$\frac{2 \cos{\left(2 x \right)}}{\sin{\left(2 x \right)}}$$

Simplify

The second derivative [src]

   /       2     \
   |    cos (2*x)|
-4*|1 + ---------|
   |       2     |
   \    sin (2*x)/

$$- 4 \cdot \left(1 + \frac{\cos^{2}{\left(2 x \right)}}{\sin^{2}{\left(2 x \right)}}\right)$$

Simplify

The third derivative [src]

   /       2     \         
   |    cos (2*x)|         
16*|1 + ---------|*cos(2*x)
   |       2     |         
   \    sin (2*x)/         
---------------------------
          sin(2*x)

$$\frac{16 \cdot \left(1 + \frac{\cos^{2}{\left(2 x \right)}}{\sin^{2}{\left(2 x \right)}}\right) \cos{\left(2 x \right)}}{\sin{\left(2 x \right)}}$$

Simplify

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Derivative of ln(sin2x)

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The solution