Mister Exam

Derivative of lnsin(2x+5)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
log(sin(2*x + 5))
log(sin(2x+5))\log{\left(\sin{\left(2 x + 5 \right)} \right)}
d                    
--(log(sin(2*x + 5)))
dx                   
ddxlog(sin(2x+5))\frac{d}{d x} \log{\left(\sin{\left(2 x + 5 \right)} \right)}
Detail solution
  1. Let u=sin(2x+5)u = \sin{\left(2 x + 5 \right)}.

  2. The derivative of log(u)\log{\left(u \right)} is 1u\frac{1}{u}.

  3. Then, apply the chain rule. Multiply by ddxsin(2x+5)\frac{d}{d x} \sin{\left(2 x + 5 \right)}:

    1. Let u=2x+5u = 2 x + 5.

    2. The derivative of sine is cosine:

      ddusin(u)=cos(u)\frac{d}{d u} \sin{\left(u \right)} = \cos{\left(u \right)}

    3. Then, apply the chain rule. Multiply by ddx(2x+5)\frac{d}{d x} \left(2 x + 5\right):

      1. Differentiate 2x+52 x + 5 term by term:

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: xx goes to 11

          So, the result is: 22

        2. The derivative of the constant 55 is zero.

        The result is: 22

      The result of the chain rule is:

      2cos(2x+5)2 \cos{\left(2 x + 5 \right)}

    The result of the chain rule is:

    2cos(2x+5)sin(2x+5)\frac{2 \cos{\left(2 x + 5 \right)}}{\sin{\left(2 x + 5 \right)}}

  4. Now simplify:

    2tan(2x+5)\frac{2}{\tan{\left(2 x + 5 \right)}}


The answer is:

2tan(2x+5)\frac{2}{\tan{\left(2 x + 5 \right)}}

The graph
02468-8-6-4-2-1010-25002500
The first derivative [src]
2*cos(2*x + 5)
--------------
 sin(2*x + 5) 
2cos(2x+5)sin(2x+5)\frac{2 \cos{\left(2 x + 5 \right)}}{\sin{\left(2 x + 5 \right)}}
The second derivative [src]
   /       2         \
   |    cos (5 + 2*x)|
-4*|1 + -------------|
   |       2         |
   \    sin (5 + 2*x)/
4(1+cos2(2x+5)sin2(2x+5))- 4 \cdot \left(1 + \frac{\cos^{2}{\left(2 x + 5 \right)}}{\sin^{2}{\left(2 x + 5 \right)}}\right)
The third derivative [src]
   /       2         \             
   |    cos (5 + 2*x)|             
16*|1 + -------------|*cos(5 + 2*x)
   |       2         |             
   \    sin (5 + 2*x)/             
-----------------------------------
            sin(5 + 2*x)           
16(1+cos2(2x+5)sin2(2x+5))cos(2x+5)sin(2x+5)\frac{16 \cdot \left(1 + \frac{\cos^{2}{\left(2 x + 5 \right)}}{\sin^{2}{\left(2 x + 5 \right)}}\right) \cos{\left(2 x + 5 \right)}}{\sin{\left(2 x + 5 \right)}}
The graph
Derivative of lnsin(2x+5)