2x²+xy-3y²=0; x²-y²+xy=4

You have entered [src]

   2            2    
2*x  + x*y - 3*y  = 0

$$- 3 y^{2} + \left(2 x^{2} + x y\right) = 0$$

 2    2          
x  - y  + x*y = 4

$$x y + \left(x^{2} - y^{2}\right) = 4$$

x*y + x^2 - y^2 = 4

Rapid solution

$$x_{1} = -2$$
=
$$-2$$
=

-2

$$y_{1} = -2$$
=
$$-2$$
=

-2

$$x_{2} = 2$$
=
$$2$$
=

$$y_{2} = 2$$
=
$$2$$
=

$$x_{3} = - 6 i$$
=
$$- 6 i$$
=

-6*i

$$y_{3} = 4 i$$
=
$$4 i$$
=

4*i

$$x_{4} = 6 i$$
=
$$6 i$$
=

6*i

$$y_{4} = - 4 i$$
=
$$- 4 i$$
=

-4*i

Numerical answer [src]

x1 = 2.0
y1 = 2.0

x2 = -2.0
y2 = -2.0

x2 = -2.0
y2 = -2.0