Log2x-3y=13; 3log2x+y=-1

You have entered [src]

log(2*x) - 3*y = 13

$$- 3 y + \log{\left(2 x \right)} = 13$$

3*log(2*x) + y = -1

$$y + 3 \log{\left(2 x \right)} = -1$$

y + 3*log(2*x) = -1

Numerical answer [src]

x1 = 1.359140914229523 + 4.94591204591952e-17*i
y1 = -4.0 + 2.010670861940281e-32*i

x2 = 1.359140914229523 + 1.211682431530782e-30*i
y2 = -4.0 + 1.177790251781432e-39*i

x3 = 1.359140914229523 - 5.678368712091804e-26*i
y3 = -4.0 + 9.045429029569634e-37*i

x4 = 1.359140914229511 - 5.691492983594231e-15*i
y4 = -4.0 + 1.488306239686555e-31*i

x5 = 1.359140914229523
y5 = -4.0

x5 = 1.359140914229523
y5 = -4.0