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2/(10^(4n+1))

Sum of series 2/(10^(4n+1))



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The solution

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  oo           
____           
\   `          
 \        2    
  \   ---------
  /     4*n + 1
 /    10       
/___,          
n = 1          
n=12104n+1\sum_{n=1}^{\infty} \frac{2}{10^{4 n + 1}}
Sum(2/10^(4*n + 1), (n, 1, oo))
The radius of convergence of the power series
Given number:
2104n+1\frac{2}{10^{4 n + 1}}
It is a series of species
an(cxx0)dna_{n} \left(c x - x_{0}\right)^{d n}
- power series.
The radius of convergence of a power series can be calculated by the formula:
Rd=x0+limnanan+1cR^{d} = \frac{x_{0} + \lim_{n \to \infty} \left|{\frac{a_{n}}{a_{n + 1}}}\right|}{c}
In this case
an=2104n1a_{n} = 2 \cdot 10^{- 4 n - 1}
and
x0=0x_{0} = 0
,
d=0d = 0
,
c=1c = 1
then
1=limn(104n1104n+5)1 = \lim_{n \to \infty}\left(10^{- 4 n - 1} \cdot 10^{4 n + 5}\right)
Let's take the limit
we find
False

False
The rate of convergence of the power series
1.07.01.52.02.53.03.54.04.55.05.56.06.50.0000199980.000020004
The answer [src]
1/49995
149995\frac{1}{49995}
1/49995
Numerical answer [src]
0.0000200020002000200020002000200020
0.0000200020002000200020002000200020
The graph
Sum of series 2/(10^(4n+1))

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