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sqrt(n)/((2*n))

How to use it?
Sum of series:
3/(n(n+2))
1/((3*n+1)*(3*n+4))
sin(3*n)/(n+2)
sqrt(n)/((2*n))
Identical expressions
sqrt(n)/((two *n))
square root of (n) divide by ((2 multiply by n))
square root of (n) divide by ((two multiply by n))
√(n)/((2*n))
sqrt(n)/((2n))
sqrtn/2n
sqrt(n) divide by ((2*n))
Similar expressions
(nsqrt(n))/(2n^2+n-1)
sqrt(n/(2n+2))
(n+sqrt(n))/(2n^2+n-1)
(n-sqrtn)/(2n^2+n-1)
(2+3sqrtn)/(2n-5)

Sum of series/ sqrt(n)/((2*n))

Sum of series sqrt(n)/((2*n))

The solution

You have entered [src]

1000000      
 ____        
 \   `       
  \       ___
   \    \/ n 
   /    -----
  /      2*n 
 /___,       
 n = 1

\sum_{n=1}^{1000000} \frac{\sqrt{n}}{2 n}

Sum(sqrt(n)/((2*n)), (n, 1, 1000000))

The rate of convergence of the power series

Numerical answer [src]

999.270072745574373260221918392

999.270072745574373260221918392

The graph

Sum of series sqrt(n)/((2*n))

Examples of finding the sum of a series

The Sum of the Power Series
```
x^n/n
```
```
(x-1)^n
```
Factorial
```
1/2^(n!)
```
```
n^2/n!
```
```
x^n/n!
```
```
k!/(n!*(n+k)!)
```
Flint Hills Series
```
csc(n)^2/n^3
```
Basel problem
```
1/n^2
```
```
1/n^4
```
```
1/n^6
```
Harmonic series
```
1/n
```
Grandi's series
```
(-1)^n
```
Alternating series
```
(-1)^(n + 1)/n
```
```
(n + 2)*(-1)^(n - 1)
```
```
(3*n - 1)/(-5)^n
```
```
(-1)^(n - 1)*n/(6*n - 5)
```
Newton–Mercator series
```
(-1)^(n + 1)/n*x^n
```
Exam the series for convergence
```
(3*n - 1)/(-5)^n
```