Mister Exam

Other calculators


1/(n(n+3)(n+6))

Sum of series 1/(n(n+3)(n+6))



=

The solution

You have entered [src]
  oo                   
 ___                   
 \  `                  
  \           1        
   )  -----------------
  /   n*(n + 3)*(n + 6)
 /__,                  
n = 1                  
n=11n(n+3)(n+6)\sum_{n=1}^{\infty} \frac{1}{n \left(n + 3\right) \left(n + 6\right)}
Sum(1/((n*(n + 3))*(n + 6)), (n, 1, oo))
The radius of convergence of the power series
Given number:
1n(n+3)(n+6)\frac{1}{n \left(n + 3\right) \left(n + 6\right)}
It is a series of species
an(cxx0)dna_{n} \left(c x - x_{0}\right)^{d n}
- power series.
The radius of convergence of a power series can be calculated by the formula:
Rd=x0+limnanan+1cR^{d} = \frac{x_{0} + \lim_{n \to \infty} \left|{\frac{a_{n}}{a_{n + 1}}}\right|}{c}
In this case
an=1n(n+3)(n+6)a_{n} = \frac{1}{n \left(n + 3\right) \left(n + 6\right)}
and
x0=0x_{0} = 0
,
d=0d = 0
,
c=1c = 1
then
1=limn((n+1)(n+4)(n+7)n(n+3)(n+6))1 = \lim_{n \to \infty}\left(\frac{\left(n + 1\right) \left(n + 4\right) \left(n + 7\right)}{n \left(n + 3\right) \left(n + 6\right)}\right)
Let's take the limit
we find
True

False
The rate of convergence of the power series
1.07.01.52.02.53.03.54.04.55.05.56.06.50.0250.075
The answer [src]
            0                  0   
  -10 + 40*e         -40 + 22*e    
---------------- + ----------------
   /          0\      /          0\
20*\-90 + 90*e /   24*\-45 + 45*e /
40+22e024(45+45e0)+10+40e020(90+90e0)\frac{-40 + 22 e^{0}}{24 \left(-45 + 45 e^{0}\right)} + \frac{-10 + 40 e^{0}}{20 \left(-90 + 90 e^{0}\right)}
(-10 + 40*exp_polar(0))/(20*(-90 + 90*exp_polar(0))) + (-40 + 22*exp_polar(0))/(24*(-45 + 45*exp_polar(0)))
Numerical answer [src]
0.0675925925925925925925925925926
0.0675925925925925925925925925926
The graph
Sum of series 1/(n(n+3)(n+6))

    Examples of finding the sum of a series