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Sum of series:
(4*9^n-2^n)/18^n
1/((3*n+1)*(3*n+4))
sqrt(n)*(x+3)^n/n^2+1
ln((n(n+2))/(n+1)^2)
Identical expressions
((- one)^(n+ two)* four ^n+ five ^(n+ one))/ seven ^(n- two)
(( minus 1) to the power of (n plus 2) multiply by 4 to the power of n plus 5 to the power of (n plus 1)) divide by 7 to the power of (n minus 2)
(( minus one) to the power of (n plus two) multiply by four to the power of n plus five to the power of (n plus one)) divide by seven to the power of (n minus two)
((-1)(n+2)*4n+5(n+1))/7(n-2)
-1n+2*4n+5n+1/7n-2
((-1)^(n+2)4^n+5^(n+1))/7^(n-2)
((-1)(n+2)4n+5(n+1))/7(n-2)
-1n+24n+5n+1/7n-2
-1^n+24^n+5^n+1/7^n-2
((-1)^(n+2)*4^n+5^(n+1)) divide by 7^(n-2)
Similar expressions
((-1)^(n+2)*4^n+5^(n+1))/7^(n+2)
((-1)^(n-2)*4^n+5^(n+1))/7^(n-2)
((-1)^(n+2)*4^n+5^(n-1))/7^(n-2)
((-1)^(n+2)*4^n-5^(n+1))/7^(n-2)
((1)^(n+2)*4^n+5^(n+1))/7^(n-2)

Sum of series/ ((-1)^(n+2)*4^n+5^(n+1))/7^(n-2)

Sum of series ((-1)^(n+2)*4^n+5^(n+1))/7^(n-2)

The solution

You have entered [src]

  oo                       
____                       
\   `                      
 \        n + 2  n    n + 1
  \   (-1)     *4  + 5     
   )  ---------------------
  /            n - 2       
 /            7            
/___,                      
n = 2

$$\sum_{n=2}^{\infty} \frac{\left(-1\right)^{n + 2} \cdot 4^{n} + 5^{n + 1}}{7^{n - 2}}$$

Sum(((-1)^(n + 2)*4^n + 5^(n + 1))/7^(n - 2), (n, 2, oo))

The rate of convergence of the power series

The answer [src]

9849
----
 22

$$\frac{9849}{22}$$

9849/22

Numerical answer [src]

447.681818181818181818181818182 + 7.14756864811027125369797136876e-53*i

447.681818181818181818181818182 + 7.14756864811027125369797136876e-53*i

The graph

Sum of series ((-1)^(n+2)*4^n+5^(n+1))/7^(n-2)

Examples of finding the sum of a series

The Sum of the Power Series
```
x^n/n
```
```
(x-1)^n
```
Factorial
```
1/2^(n!)
```
```
n^2/n!
```
```
x^n/n!
```
```
k!/(n!*(n+k)!)
```
Flint Hills Series
```
csc(n)^2/n^3
```
Basel problem
```
1/n^2
```
```
1/n^4
```
```
1/n^6
```
Harmonic series
```
1/n
```
Grandi's series
```
(-1)^n
```
Alternating series
```
(-1)^(n + 1)/n
```
```
(n + 2)*(-1)^(n - 1)
```
```
(3*n - 1)/(-5)^n
```
```
(-1)^(n - 1)*n/(6*n - 5)
```
Newton–Mercator series
```
(-1)^(n + 1)/n*x^n
```
Exam the series for convergence
```
(3*n - 1)/(-5)^n
```

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Identical expressions

Similar expressions

Sum of series ((-1)^(n+2)*4^n+5^(n+1))/7^(n-2)

The solution

Examples of finding the sum of a series