Mister Exam
Other calculators
- Taylor Series Step by Step
- Fourier series step by step
- Differential equations Step by Step
- Product of series
-
How to use it?
- Sum of series:
-
(-1)^n
-
7+k
-
1/((2n-1)(2n+1))
-
sqrt(n^3+2)/(n^2+3)
-
Identical expressions
- ((- one)^(n+ one))/(n*(n+ one)*(n+ two))
- (( minus 1) to the power of (n plus 1)) divide by (n multiply by (n plus 1) multiply by (n plus 2))
- (( minus one) to the power of (n plus one)) divide by (n multiply by (n plus one) multiply by (n plus two))
- ((-1)(n+1))/(n*(n+1)*(n+2))
- -1n+1/n*n+1*n+2
- ((-1)^(n+1))/(n(n+1)(n+2))
- ((-1)(n+1))/(n(n+1)(n+2))
- -1n+1/nn+1n+2
- -1^n+1/nn+1n+2
- ((-1)^(n+1)) divide by (n*(n+1)*(n+2))
-
Similar expressions
- ((1)^(n+1))/(n*(n+1)*(n+2))
- ((-1)^(n-1))/(n*(n+1)*(n+2))
- ((-1)^(n+1))/(n*(n-1)*(n+2))
- ((-1)^(n+1))/(n*(n+1)*(n-2))
Sum of series ((-1)^(n+1))/(n*(n+1)*(n+2))
The solution
You have entered
[src]
oo ____ \ ` \ n + 1 \ (-1) / ----------------- / n*(n + 1)*(n + 2) /___, n = 1
$$\sum_{n=1}^{\infty} \frac{\left(-1\right)^{n + 1}}{n \left(n + 1\right) \left(n + 2\right)}$$
Sum((-1)^(n + 1)/(((n*(n + 1))*(n + 2))), (n, 1, oo))
The radius of convergence of the power series
Given number:
$$\frac{\left(-1\right)^{n + 1}}{n \left(n + 1\right) \left(n + 2\right)}$$
It is a series of species
$$a_{n} \left(c x - x_{0}\right)^{d n}$$
- power series.
The radius of convergence of a power series can be calculated by the formula:
$$R^{d} = \frac{x_{0} + \lim_{n \to \infty} \left|{\frac{a_{n}}{a_{n + 1}}}\right|}{c}$$
In this case
$$a_{n} = \frac{\left(-1\right)^{n + 1}}{n \left(n + 1\right) \left(n + 2\right)}$$
and
$$x_{0} = 0$$
,
$$d = 0$$
,
$$c = 1$$
then
$$1 = \lim_{n \to \infty}\left(\frac{n + 3}{n}\right)$$
Let's take the limit
we find
$$\frac{\left(-1\right)^{n + 1}}{n \left(n + 1\right) \left(n + 2\right)}$$
It is a series of species
$$a_{n} \left(c x - x_{0}\right)^{d n}$$
- power series.
The radius of convergence of a power series can be calculated by the formula:
$$R^{d} = \frac{x_{0} + \lim_{n \to \infty} \left|{\frac{a_{n}}{a_{n + 1}}}\right|}{c}$$
In this case
$$a_{n} = \frac{\left(-1\right)^{n + 1}}{n \left(n + 1\right) \left(n + 2\right)}$$
and
$$x_{0} = 0$$
,
$$d = 0$$
,
$$c = 1$$
then
$$1 = \lim_{n \to \infty}\left(\frac{n + 3}{n}\right)$$
Let's take the limit
we find
True
False
The rate of convergence of the power series
The graph
Examples of finding the sum of a series
- The Sum of the Power Series
x^n/n
(x-1)^n
- Factorial
1/2^(n!)
n^2/n!
x^n/n!
k!/(n!*(n+k)!)
- Flint Hills Series
csc(n)^2/n^3
- Basel problem
1/n^2
1/n^4
1/n^6
- Harmonic series
1/n
- Grandi's series
(-1)^n
- Alternating series
(-1)^(n + 1)/n
(n + 2)*(-1)^(n - 1)
(3*n - 1)/(-5)^n
(-1)^(n - 1)*n/(6*n - 5)
- Newton–Mercator series
(-1)^(n + 1)/n*x^n
- Exam the series for convergence
(3*n - 1)/(-5)^n