Mister Exam

Other calculators

Sum of series ln((1-x)/(1+x))



=

The solution

You have entered [src]
  oo            
 ___            
 \  `           
  \      /1 - x\
   )  log|-----|
  /      \1 + x/
 /__,           
n = 1           
n=1log(1xx+1)\sum_{n=1}^{\infty} \log{\left(\frac{1 - x}{x + 1} \right)}
Sum(log((1 - x)/(1 + x)), (n, 1, oo))
The radius of convergence of the power series
Given number:
log(1xx+1)\log{\left(\frac{1 - x}{x + 1} \right)}
It is a series of species
an(cxx0)dna_{n} \left(c x - x_{0}\right)^{d n}
- power series.
The radius of convergence of a power series can be calculated by the formula:
Rd=x0+limnanan+1cR^{d} = \frac{x_{0} + \lim_{n \to \infty} \left|{\frac{a_{n}}{a_{n + 1}}}\right|}{c}
In this case
an=log(1xx+1)a_{n} = \log{\left(\frac{1 - x}{x + 1} \right)}
and
x0=0x_{0} = 0
,
d=0d = 0
,
c=1c = 1
then
1=limn11 = \lim_{n \to \infty} 1
Let's take the limit
we find
True

False
The answer [src]
      /1 - x\
oo*log|-----|
      \1 + x/
log(1xx+1)\infty \log{\left(\frac{1 - x}{x + 1} \right)}
oo*log((1 - x)/(1 + x))

    Examples of finding the sum of a series