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4.2*405*4

Sum of series 4.2*405*4



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The solution

You have entered [src]
  oo          
 ___          
 \  `         
  \   21*405  
   )  ------*4
  /     5     
 /__,         
i = 1         
$$\sum_{i=1}^{\infty} 4 \frac{21 \cdot 405}{5}$$
Sum((21*405/5)*4, (i, 1, oo))
The radius of convergence of the power series
Given number:
$$4 \frac{21 \cdot 405}{5}$$
It is a series of species
$$a_{i} \left(c x - x_{0}\right)^{d i}$$
- power series.
The radius of convergence of a power series can be calculated by the formula:
$$R^{d} = \frac{x_{0} + \lim_{i \to \infty} \left|{\frac{a_{i}}{a_{i + 1}}}\right|}{c}$$
In this case
$$a_{i} = 6804$$
and
$$x_{0} = 0$$
,
$$d = 0$$
,
$$c = 1$$
then
$$1 = \lim_{i \to \infty} 1$$
Let's take the limit
we find
True

False
The rate of convergence of the power series
The answer [src]
oo
$$\infty$$
oo
Numerical answer
The series diverges
The graph
Sum of series 4.2*405*4

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