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arctan(n+3)-arctan(n+1)

Sum of series arctan(n+3)-arctan(n+1)



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The solution

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  oo                             
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  )   (atan(n + 3) - atan(n + 1))
 /_,                             
n = 1                            
n=1(atan(n+1)+atan(n+3))\sum_{n=1}^{\infty} \left(- \operatorname{atan}{\left(n + 1 \right)} + \operatorname{atan}{\left(n + 3 \right)}\right)
Sum(atan(n + 3) - atan(n + 1), (n, 1, oo))
The radius of convergence of the power series
Given number:
atan(n+1)+atan(n+3)- \operatorname{atan}{\left(n + 1 \right)} + \operatorname{atan}{\left(n + 3 \right)}
It is a series of species
an(cxx0)dna_{n} \left(c x - x_{0}\right)^{d n}
- power series.
The radius of convergence of a power series can be calculated by the formula:
Rd=x0+limnanan+1cR^{d} = \frac{x_{0} + \lim_{n \to \infty} \left|{\frac{a_{n}}{a_{n + 1}}}\right|}{c}
In this case
an=atan(n+1)+atan(n+3)a_{n} = - \operatorname{atan}{\left(n + 1 \right)} + \operatorname{atan}{\left(n + 3 \right)}
and
x0=0x_{0} = 0
,
d=0d = 0
,
c=1c = 1
then
1=limnatan(n+1)atan(n+3)atan(n+2)atan(n+4)1 = \lim_{n \to \infty} \left|{\frac{\operatorname{atan}{\left(n + 1 \right)} - \operatorname{atan}{\left(n + 3 \right)}}{\operatorname{atan}{\left(n + 2 \right)} - \operatorname{atan}{\left(n + 4 \right)}}}\right|
Let's take the limit
we find
True

False
The rate of convergence of the power series
1.07.01.52.02.53.03.54.04.55.05.56.06.50.01.0
The answer [src]
pi - atan(2) - atan(3)
atan(3)atan(2)+π- \operatorname{atan}{\left(3 \right)} - \operatorname{atan}{\left(2 \right)} + \pi
pi - atan(2) - atan(3)
Numerical answer [src]
0.785398163397448309615660845820
0.785398163397448309615660845820
The graph
Sum of series arctan(n+3)-arctan(n+1)

    Examples of finding the sum of a series