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Factor y^4-y^2+1 squared

An expression to simplify:

The solution

You have entered [src]
 4    2    
y  - y  + 1
$$\left(y^{4} - y^{2}\right) + 1$$
y^4 - y^2 + 1
General simplification [src]
     4    2
1 + y  - y 
$$y^{4} - y^{2} + 1$$
1 + y^4 - y^2
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(y^{4} - y^{2}\right) + 1$$
To do this, let's use the formula
$$a y^{4} + b y^{2} + c = a \left(m + y^{2}\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = -1$$
$$c = 1$$
Then
$$m = - \frac{1}{2}$$
$$n = \frac{3}{4}$$
So,
$$\left(y^{2} - \frac{1}{2}\right)^{2} + \frac{3}{4}$$
Factorization [src]
/          ___\ /            ___\ /        ___    \ /            ___\
|    I   \/ 3 | |      I   \/ 3 | |      \/ 3    I| |      I   \/ 3 |
|x + - + -----|*|x + - - + -----|*|x + - ----- + -|*|x + - - - -----|
\    2     2  / \      2     2  / \        2     2/ \      2     2  /
$$\left(x + \left(\frac{\sqrt{3}}{2} - \frac{i}{2}\right)\right) \left(x + \left(\frac{\sqrt{3}}{2} + \frac{i}{2}\right)\right) \left(x + \left(- \frac{\sqrt{3}}{2} + \frac{i}{2}\right)\right) \left(x + \left(- \frac{\sqrt{3}}{2} - \frac{i}{2}\right)\right)$$
(((x + i/2 + sqrt(3)/2)*(x - i/2 + sqrt(3)/2))*(x - sqrt(3)/2 + i/2))*(x - i/2 - sqrt(3)/2)
Trigonometric part [src]
     4    2
1 + y  - y 
$$y^{4} - y^{2} + 1$$
1 + y^4 - y^2
Combinatorics [src]
     4    2
1 + y  - y 
$$y^{4} - y^{2} + 1$$
1 + y^4 - y^2
Rational denominator [src]
     4    2
1 + y  - y 
$$y^{4} - y^{2} + 1$$
1 + y^4 - y^2
Common denominator [src]
     4    2
1 + y  - y 
$$y^{4} - y^{2} + 1$$
1 + y^4 - y^2
Numerical answer [src]
1.0 + y^4 - y^2
1.0 + y^4 - y^2
Assemble expression [src]
     4    2
1 + y  - y 
$$y^{4} - y^{2} + 1$$
1 + y^4 - y^2
Powers [src]
     4    2
1 + y  - y 
$$y^{4} - y^{2} + 1$$
1 + y^4 - y^2
Combining rational expressions [src]
     2 /      2\
1 + y *\-1 + y /
$$y^{2} \left(y^{2} - 1\right) + 1$$
1 + y^2*(-1 + y^2)