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Factor y^4-4*y^2-3 squared

An expression to simplify:

The solution

You have entered [src]
 4      2    
y  - 4*y  - 3
$$\left(y^{4} - 4 y^{2}\right) - 3$$
y^4 - 4*y^2 - 3
General simplification [src]
      4      2
-3 + y  - 4*y 
$$y^{4} - 4 y^{2} - 3$$
-3 + y^4 - 4*y^2
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(y^{4} - 4 y^{2}\right) - 3$$
To do this, let's use the formula
$$a y^{4} + b y^{2} + c = a \left(m + y^{2}\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = -4$$
$$c = -3$$
Then
$$m = -2$$
$$n = -7$$
So,
$$\left(y^{2} - 2\right)^{2} - 7$$
Factorization [src]
/         ____________\ /         ____________\ /       ___________\ /       ___________\
|        /        ___ | |        /        ___ | |      /       ___ | |      /       ___ |
\x + I*\/  -2 + \/ 7  /*\x - I*\/  -2 + \/ 7  /*\x + \/  2 + \/ 7  /*\x - \/  2 + \/ 7  /
$$\left(x - i \sqrt{-2 + \sqrt{7}}\right) \left(x + i \sqrt{-2 + \sqrt{7}}\right) \left(x + \sqrt{2 + \sqrt{7}}\right) \left(x - \sqrt{2 + \sqrt{7}}\right)$$
(((x + i*sqrt(-2 + sqrt(7)))*(x - i*sqrt(-2 + sqrt(7))))*(x + sqrt(2 + sqrt(7))))*(x - sqrt(2 + sqrt(7)))
Common denominator [src]
      4      2
-3 + y  - 4*y 
$$y^{4} - 4 y^{2} - 3$$
-3 + y^4 - 4*y^2
Trigonometric part [src]
      4      2
-3 + y  - 4*y 
$$y^{4} - 4 y^{2} - 3$$
-3 + y^4 - 4*y^2
Numerical answer [src]
-3.0 + y^4 - 4.0*y^2
-3.0 + y^4 - 4.0*y^2
Assemble expression [src]
      4      2
-3 + y  - 4*y 
$$y^{4} - 4 y^{2} - 3$$
-3 + y^4 - 4*y^2
Combinatorics [src]
      4      2
-3 + y  - 4*y 
$$y^{4} - 4 y^{2} - 3$$
-3 + y^4 - 4*y^2
Powers [src]
      4      2
-3 + y  - 4*y 
$$y^{4} - 4 y^{2} - 3$$
-3 + y^4 - 4*y^2
Rational denominator [src]
      4      2
-3 + y  - 4*y 
$$y^{4} - 4 y^{2} - 3$$
-3 + y^4 - 4*y^2
Combining rational expressions [src]
      2 /      2\
-3 + y *\-4 + y /
$$y^{2} \left(y^{2} - 4\right) - 3$$
-3 + y^2*(-4 + y^2)