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How do you (2x+5)/(x^2-2x+5) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
  2*x + 5   
------------
 2          
x  - 2*x + 5
$$\frac{2 x + 5}{\left(x^{2} - 2 x\right) + 5}$$
(2*x + 5)/(x^2 - 2*x + 5)
Fraction decomposition [src]
(5 + 2*x)/(5 + x^2 - 2*x)
$$\frac{2 x + 5}{x^{2} - 2 x + 5}$$
  5 + 2*x   
------------
     2      
5 + x  - 2*x
General simplification [src]
  5 + 2*x   
------------
     2      
5 + x  - 2*x
$$\frac{2 x + 5}{x^{2} - 2 x + 5}$$
(5 + 2*x)/(5 + x^2 - 2*x)
Trigonometric part [src]
  5 + 2*x   
------------
     2      
5 + x  - 2*x
$$\frac{2 x + 5}{x^{2} - 2 x + 5}$$
(5 + 2*x)/(5 + x^2 - 2*x)
Numerical answer [src]
(5.0 + 2.0*x)/(5.0 + x^2 - 2.0*x)
(5.0 + 2.0*x)/(5.0 + x^2 - 2.0*x)
Assemble expression [src]
  5 + 2*x   
------------
     2      
5 + x  - 2*x
$$\frac{2 x + 5}{x^{2} - 2 x + 5}$$
(5 + 2*x)/(5 + x^2 - 2*x)
Combinatorics [src]
  5 + 2*x   
------------
     2      
5 + x  - 2*x
$$\frac{2 x + 5}{x^{2} - 2 x + 5}$$
(5 + 2*x)/(5 + x^2 - 2*x)
Common denominator [src]
  5 + 2*x   
------------
     2      
5 + x  - 2*x
$$\frac{2 x + 5}{x^{2} - 2 x + 5}$$
(5 + 2*x)/(5 + x^2 - 2*x)
Rational denominator [src]
  5 + 2*x   
------------
     2      
5 + x  - 2*x
$$\frac{2 x + 5}{x^{2} - 2 x + 5}$$
(5 + 2*x)/(5 + x^2 - 2*x)
Combining rational expressions [src]
   5 + 2*x    
--------------
5 + x*(-2 + x)
$$\frac{2 x + 5}{x \left(x - 2\right) + 5}$$
(5 + 2*x)/(5 + x*(-2 + x))
Powers [src]
  5 + 2*x   
------------
     2      
5 + x  - 2*x
$$\frac{2 x + 5}{x^{2} - 2 x + 5}$$
(5 + 2*x)/(5 + x^2 - 2*x)