Mister Exam
Other calculators
-
How to use it?
- Factor squared:
- y^4+6*y^2+7
- y^4-6*y^2-6
- y^4+7*y^2-8
- y^4-6*y^2+5
- Factor polynomial:
- z^3+3*z^2+4*z+12-0
- z^2+d/z-2
- z^2-6*z+5
- z^2+6*z+1
- Least common denominator:
- (x/y)-(y/x)-y/x+y-1
- ((x*y)+sin(x))/(|1-y|*(log(x)/log(10)))
- (x*y+10*y^2/2-5*(y-1)^2-(x-10)*(y-1))/((x-10)*(y-1)+10*(y-1)^2/2-5*(y-2)^2-(x-20)*(y-2))
- x/x+6*y/5-x*y-2*x^2/x^2-7*y^2/5
- How do you in partial fractions?:
- x^3/(x^4-1)
- sqrt(1-((1-x*x)*(n0*n0)/(n1*n1)))
- (x^2-2*x+1)/(x-1)
- -tan(-1/2+x)/(-1+tan(-1/2+x)^2)
- Derivative of:
-
2*x^2-3*x+1
- Factor polynomial:
- 2*x^2-3*x+1
-
Identical expressions
- two *x^ two - three *x+ one
- 2 multiply by x squared minus 3 multiply by x plus 1
- two multiply by x to the power of two minus three multiply by x plus one
- 2*x2-3*x+1
- 2*x²-3*x+1
- 2*x to the power of 2-3*x+1
- 2x^2-3x+1
- 2x2-3x+1
-
Similar expressions
- 2*x^2+3*x+1
- 2*x^2-3*x-1
Factor 2*x^2-3*x+1 squared
The solution
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(2 x^{2} - 3 x\right) + 1$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 2$$
$$b = -3$$
$$c = 1$$
Then
$$m = - \frac{3}{4}$$
$$n = - \frac{1}{8}$$
So,
$$2 \left(x - \frac{3}{4}\right)^{2} - \frac{1}{8}$$
$$\left(2 x^{2} - 3 x\right) + 1$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 2$$
$$b = -3$$
$$c = 1$$
Then
$$m = - \frac{3}{4}$$
$$n = - \frac{1}{8}$$
So,
$$2 \left(x - \frac{3}{4}\right)^{2} - \frac{1}{8}$$
Factorization
[src]
(x - 1/2)*(x - 1)
$$\left(x - 1\right) \left(x - \frac{1}{2}\right)$$
(x - 1/2)*(x - 1)
Combinatorics
[src]
(-1 + x)*(-1 + 2*x)
$$\left(x - 1\right) \left(2 x - 1\right)$$
(-1 + x)*(-1 + 2*x)
Combining rational expressions
[src]
1 + x*(-3 + 2*x)
$$x \left(2 x - 3\right) + 1$$
1 + x*(-3 + 2*x)