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How do you (x^2-2*x+1)/(x-1) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
 2          
x  - 2*x + 1
------------
   x - 1    
$$\frac{\left(x^{2} - 2 x\right) + 1}{x - 1}$$
(x^2 - 2*x + 1)/(x - 1)
Fraction decomposition [src]
-1 + x
$$x - 1$$
-1 + x
General simplification [src]
-1 + x
$$x - 1$$
-1 + x
Assemble expression [src]
     2      
1 + x  - 2*x
------------
   -1 + x   
$$\frac{x^{2} - 2 x + 1}{x - 1}$$
(1 + x^2 - 2*x)/(-1 + x)
Numerical answer [src]
(1.0 + x^2 - 2.0*x)/(-1.0 + x)
(1.0 + x^2 - 2.0*x)/(-1.0 + x)
Common denominator [src]
-1 + x
$$x - 1$$
-1 + x
Combining rational expressions [src]
1 + x*(-2 + x)
--------------
    -1 + x    
$$\frac{x \left(x - 2\right) + 1}{x - 1}$$
(1 + x*(-2 + x))/(-1 + x)
Combinatorics [src]
-1 + x
$$x - 1$$
-1 + x
Trigonometric part [src]
     2      
1 + x  - 2*x
------------
   -1 + x   
$$\frac{x^{2} - 2 x + 1}{x - 1}$$
(1 + x^2 - 2*x)/(-1 + x)
Powers [src]
     2      
1 + x  - 2*x
------------
   -1 + x   
$$\frac{x^{2} - 2 x + 1}{x - 1}$$
(1 + x^2 - 2*x)/(-1 + x)
Rational denominator [src]
     2      
1 + x  - 2*x
------------
   -1 + x   
$$\frac{x^{2} - 2 x + 1}{x - 1}$$
(1 + x^2 - 2*x)/(-1 + x)