General simplification
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$$2 x^{2} - 3 x + 1$$
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(2 x^{2} - 3 x\right) + 1$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 2$$
$$b = -3$$
$$c = 1$$
Then
$$m = - \frac{3}{4}$$
$$n = - \frac{1}{8}$$
So,
$$2 \left(x - \frac{3}{4}\right)^{2} - \frac{1}{8}$$
$$\left(x - 1\right) \left(x - \frac{1}{2}\right)$$
Combining rational expressions
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$$x \left(2 x - 3\right) + 1$$
$$\left(x - 1\right) \left(2 x - 1\right)$$
Assemble expression
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$$2 x^{2} - 3 x + 1$$
Rational denominator
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$$2 x^{2} - 3 x + 1$$