General simplification
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$$8 x^{2} + 8 x y - y^{2}$$
The perfect square
Let's highlight the perfect square of the square three-member
$$8 x^{2} + \left(x 8 y - y^{2}\right)$$
Let us write down the identical expression
$$8 x^{2} + \left(x 8 y - y^{2}\right) = - 3 y^{2} + \left(8 x^{2} + 8 x y + 2 y^{2}\right)$$
or
$$8 x^{2} + \left(x 8 y - y^{2}\right) = - 3 y^{2} + \left(2 \sqrt{2} x + \sqrt{2} y\right)^{2}$$
in the view of the product
$$\left(- \sqrt{3} y + \left(2 \sqrt{2} x + \sqrt{2} y\right)\right) \left(\sqrt{3} y + \left(2 \sqrt{2} x + \sqrt{2} y\right)\right)$$
$$\left(- \sqrt{3} y + \left(2 \sqrt{2} x + \sqrt{2} y\right)\right) \left(\sqrt{3} y + \left(2 \sqrt{2} x + \sqrt{2} y\right)\right)$$
$$\left(2 \sqrt{2} x + y \left(\sqrt{2} + \sqrt{3}\right)\right) \left(2 \sqrt{2} x + y \left(- \sqrt{3} + \sqrt{2}\right)\right)$$
$$\left(2 \sqrt{2} x + y \left(\sqrt{2} + \sqrt{3}\right)\right) \left(2 \sqrt{2} x + y \left(- \sqrt{3} + \sqrt{2}\right)\right)$$
/ / ___\\ / / ___\\
| y*\-2 + \/ 6 /| | y*\2 + \/ 6 /|
|x - --------------|*|x + -------------|
\ 4 / \ 4 /
$$\left(x - \frac{y \left(-2 + \sqrt{6}\right)}{4}\right) \left(x + \frac{y \left(2 + \sqrt{6}\right)}{4}\right)$$
(x - y*(-2 + sqrt(6))/4)*(x + y*(2 + sqrt(6))/4)
$$8 x^{2} + 8 x y - y^{2}$$
$$8 x^{2} + 8 x y - y^{2}$$
Rational denominator
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$$8 x^{2} + 8 x y - y^{2}$$
$$8 x^{2} + 8 x y - y^{2}$$
Combining rational expressions
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$$8 x^{2} + y \left(8 x - y\right)$$
$$8 x^{2} + 8 x y - y^{2}$$
Assemble expression
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$$8 x^{2} + 8 x y - y^{2}$$