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How do you (7^(1/3))^3/(log27) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
      3
 3 ___ 
 \/ 7  
-------
log(27)
$$\frac{\left(\sqrt[3]{7}\right)^{3}}{\log{\left(27 \right)}}$$
(7^(1/3))^3/log(27)
Fraction decomposition [src]
7/(3*log(3))
$$\frac{7}{3 \log{\left(3 \right)}}$$
   7    
--------
3*log(3)
General simplification [src]
   7   
-------
log(27)
$$\frac{7}{\log{\left(27 \right)}}$$
7/log(27)
Numerical answer [src]
2.12389152879595
2.12389152879595
Powers [src]
   7   
-------
log(27)
$$\frac{7}{\log{\left(27 \right)}}$$
7/log(27)
Combinatorics [src]
   7    
--------
3*log(3)
$$\frac{7}{3 \log{\left(3 \right)}}$$
7/(3*log(3))
Combining rational expressions [src]
   7   
-------
log(27)
$$\frac{7}{\log{\left(27 \right)}}$$
7/log(27)
Common denominator [src]
   7    
--------
3*log(3)
$$\frac{7}{3 \log{\left(3 \right)}}$$
7/(3*log(3))
Trigonometric part [src]
   7   
-------
log(27)
$$\frac{7}{\log{\left(27 \right)}}$$
7/log(27)
Rational denominator [src]
   7   
-------
log(27)
$$\frac{7}{\log{\left(27 \right)}}$$
7/log(27)