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How to use it?
How do you in partial fractions?
:
(4x-1)/(x^2-4x+8)
(x^3+2)/(x^3-4x)
x^2/(1-x^4)
(25a^2-9)/(5a+3)
Factor polynomial
:
x*z^5+x*y^5-y*z^5-y^6
x*y+y^2*x/8
x-y+y^2
x*y*x-x*y
Least common denominator
:
-x^2/(x-1)^2+2*x/(x-1)
x^2-91/10-3*x*2/(x-4)-4*x*(-1)/((x^2-x-12)*(x+3))
((x+1)*x/2*(2*x+1))+(k+1)^2/((2*k+1)*(2*k+3))
x*(-1/(exp(1)-1)+2*a*x-a*e-a)^2+2*(1-x)/(exp(1)-1)+1+a*(x-1)*(x-exp(1))
Factor squared
:
-y^2+y*x+9*x^2
y^2+y*x-8*x^2
y^4-14*y^2-11
y^4-14*y^2+1
Identical expressions
(two 5a^2- nine)/(5a+ three)
(25a squared minus 9) divide by (5a plus 3)
(two 5a squared minus nine) divide by (5a plus three)
(25a2-9)/(5a+3)
25a2-9/5a+3
(25a²-9)/(5a+3)
(25a to the power of 2-9)/(5a+3)
25a^2-9/5a+3
(25a^2-9) divide by (5a+3)
Similar expressions
(25a^2-9)/(5a-3)
(25a^2+9)/(5a+3)
Expression simplification
/
Fraction Decomposition into the simple
/
(25a^2-9)/(5a+3)
How do you (25a^2-9)/(5a+3) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
2 25*a - 9 --------- 5*a + 3
$$\frac{25 a^{2} - 9}{5 a + 3}$$
(25*a^2 - 9)/(5*a + 3)
Fraction decomposition
[src]
-3 + 5*a
$$5 a - 3$$
-3 + 5*a
General simplification
[src]
-3 + 5*a
$$5 a - 3$$
-3 + 5*a
Numerical answer
[src]
(-9.0 + 25.0*a^2)/(3.0 + 5.0*a)
(-9.0 + 25.0*a^2)/(3.0 + 5.0*a)
Common denominator
[src]
-3 + 5*a
$$5 a - 3$$
-3 + 5*a
Combinatorics
[src]
-3 + 5*a
$$5 a - 3$$
-3 + 5*a