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How to use it?
How do you in partial fractions?
:
x^2-9/(x+3)^2
(x^3+2)/(x^3-4x)
(C^2-5c)/(c^2-25)
(25a^2-9)/(5a+3)
Factor polynomial
:
y^2/y-8-64/y-8
y^2-y^8
y^2+y-6
y^2+y^3
Least common denominator
:
((x^4+3)*(-(x^3*(x^4-3))/((x^4+3)^2)+x^3/(x^4+3)))/(x^4-3)
x^3/(x^2-64)-x/(x-8)+2/(x+8)
-x^3/(x-1)^2+3*x^2/(x-1)
(x+3/(6*x-30))*(450/(x^2+3*x))
Factor squared
:
-y^4-12*y^2+11
-y^4+11*y^2-9
y^4+11*y^2+15
-y^2-y*x+3*x^2
Identical expressions
(two 5a^2- nine)/(5a+ three)
(25a squared minus 9) divide by (5a plus 3)
(two 5a squared minus nine) divide by (5a plus three)
(25a2-9)/(5a+3)
25a2-9/5a+3
(25a²-9)/(5a+3)
(25a to the power of 2-9)/(5a+3)
25a^2-9/5a+3
(25a^2-9) divide by (5a+3)
Similar expressions
(25a^2-9)/(5a-3)
(25a^2+9)/(5a+3)
Expression simplification
/
Fraction Decomposition into the simple
/
(25a^2-9)/(5a+3)
How do you (25a^2-9)/(5a+3) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
2 25*a - 9 --------- 5*a + 3
$$\frac{25 a^{2} - 9}{5 a + 3}$$
(25*a^2 - 9)/(5*a + 3)
Fraction decomposition
[src]
-3 + 5*a
$$5 a - 3$$
-3 + 5*a
General simplification
[src]
-3 + 5*a
$$5 a - 3$$
-3 + 5*a
Numerical answer
[src]
(-9.0 + 25.0*a^2)/(3.0 + 5.0*a)
(-9.0 + 25.0*a^2)/(3.0 + 5.0*a)
Common denominator
[src]
-3 + 5*a
$$5 a - 3$$
-3 + 5*a
Combinatorics
[src]
-3 + 5*a
$$5 a - 3$$
-3 + 5*a