Mister Exam

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How do you in partial fractions?:
(9-m^2)/(m^2+3*m)
(x^2-3*x+2)/(x+4)
(6/(a-1)-10/(a-1)^2)/(10/(a^2-1)-(2*a+2)/(a-1))
-10-7*((x-2)/2-3/(x-2))+18/(x-2)^2+(x-2)^2/2
Factor polynomial:
z^3+5*z^2
z^3-4*z^2+14*z-20
z^3-3*z^2+z+5
z^3+3*z^2+4*z+12
Least common denominator:
y/(4*y+16)+(y^2+16)/(4*y^2-64)-(4/(y^2-4*y))
y^(2*n-4)*y^n/(y^n+1-5*y)-(7*y^n-30)/(y^n+1-5*y)
((x/(y-x))^-2)*((x^2+x*y)/(((x+y)^2)-4*x*y))
(x/y^2-x*y+x-y/x^2-x*y)/(y^2/x^3-x*y^2+1/x-y)
Factor squared:
-y^4+8*y^2-13
-y^4+9*y^2+6
-y^4+7*y^2+6
-y^4-7*y^2-7
Identical expressions
(nine -m^ two)/(m^ two + three *m)
(9 minus m squared ) divide by (m squared plus 3 multiply by m)
(nine minus m to the power of two) divide by (m to the power of two plus three multiply by m)
(9-m2)/(m2+3*m)
9-m2/m2+3*m
(9-m²)/(m²+3*m)
(9-m to the power of 2)/(m to the power of 2+3*m)
(9-m^2)/(m^2+3m)
(9-m2)/(m2+3m)
9-m2/m2+3m
9-m^2/m^2+3m
(9-m^2) divide by (m^2+3*m)
Similar expressions
(9+m^2)/(m^2+3*m)
(9-m^2)/(m^2-3*m)

How do you (9-m^2)/(m^2+3*m) in partial fractions?

You have entered [src]

      2 
 9 - m  
--------
 2      
m  + 3*m

$$\frac{9 - m^{2}}{m^{2} + 3 m}$$

(9 - m^2)/(m^2 + 3*m)

Fraction decomposition [src]

-1 + 3/m

$$-1 + \frac{3}{m}$$

     3
-1 + -
     m

General simplification [src]

3 - m
-----
  m

$$\frac{3 - m}{m}$$

(3 - m)/m

Numerical answer [src]

(9.0 - m^2)/(m^2 + 3.0*m)

(9.0 - m^2)/(m^2 + 3.0*m)

Common denominator [src]

     3
-1 + -
     m

$$-1 + \frac{3}{m}$$

-1 + 3/m

Combining rational expressions [src]

       2 
  9 - m  
---------
m*(3 + m)

$$\frac{9 - m^{2}}{m \left(m + 3\right)}$$

(9 - m^2)/(m*(3 + m))

Combinatorics [src]

-(-3 + m) 
----------
    m

$$- \frac{m - 3}{m}$$

-(-3 + m)/m