Mister Exam
How do you (x^2-3*x+2)/(x+4) in partial fractions?
The solution
You have entered
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2 x - 3*x + 2 ------------ x + 4
$$\frac{\left(x^{2} - 3 x\right) + 2}{x + 4}$$
(x^2 - 3*x + 2)/(x + 4)
Fraction decomposition
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-7 + x + 30/(4 + x)
$$x - 7 + \frac{30}{x + 4}$$
30
-7 + x + -----
4 + x
General simplification
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2 2 + x - 3*x ------------ 4 + x
$$\frac{x^{2} - 3 x + 2}{x + 4}$$
(2 + x^2 - 3*x)/(4 + x)
Trigonometric part
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2 2 + x - 3*x ------------ 4 + x
$$\frac{x^{2} - 3 x + 2}{x + 4}$$
(2 + x^2 - 3*x)/(4 + x)
Combining rational expressions
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2 + x*(-3 + x)
--------------
4 + x
$$\frac{x \left(x - 3\right) + 2}{x + 4}$$
(2 + x*(-3 + x))/(4 + x)
Rational denominator
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2 2 + x - 3*x ------------ 4 + x
$$\frac{x^{2} - 3 x + 2}{x + 4}$$
(2 + x^2 - 3*x)/(4 + x)
Powers
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2 2 + x - 3*x ------------ 4 + x
$$\frac{x^{2} - 3 x + 2}{x + 4}$$
(2 + x^2 - 3*x)/(4 + x)
Assemble expression
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2 2 + x - 3*x ------------ 4 + x
$$\frac{x^{2} - 3 x + 2}{x + 4}$$
(2 + x^2 - 3*x)/(4 + x)
Combinatorics
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(-1 + x)*(-2 + x)
-----------------
4 + x
$$\frac{\left(x - 2\right) \left(x - 1\right)}{x + 4}$$
(-1 + x)*(-2 + x)/(4 + x)