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How do you 1/(n*(n+1)*(n+2)) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
        1        
-----------------
n*(n + 1)*(n + 2)
$$\frac{1}{n \left(n + 1\right) \left(n + 2\right)}$$
1/((n*(n + 1))*(n + 2))
Fraction decomposition [src]
1/(2*n) + 1/(2*(2 + n)) - 1/(1 + n)
$$\frac{1}{2 \left(n + 2\right)} - \frac{1}{n + 1} + \frac{1}{2 n}$$
 1        1         1  
--- + --------- - -----
2*n   2*(2 + n)   1 + n
Numerical answer [src]
1/(n*(1.0 + n)*(2.0 + n))
1/(n*(1.0 + n)*(2.0 + n))
Expand expression [src]
/    1    \
|---------|
\n*(n + 1)/
-----------
   n + 2   
$$\frac{\frac{1}{n} \frac{1}{n + 1}}{n + 2}$$
(1/(n*(n + 1)))/(n + 2)
Common denominator [src]
       1       
---------------
 3            2
n  + 2*n + 3*n 
$$\frac{1}{n^{3} + 3 n^{2} + 2 n}$$
1/(n^3 + 2*n + 3*n^2)