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How do you (z+1)/(z+2)^3/(z-1) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
/ z + 1  \
|--------|
|       3|
\(z + 2) /
----------
  z - 1   
$$\frac{\left(z + 1\right) \frac{1}{\left(z + 2\right)^{3}}}{z - 1}$$
((z + 1)/(z + 2)^3)/(z - 1)
General simplification [src]
      1 + z      
-----------------
                3
(-1 + z)*(2 + z) 
$$\frac{z + 1}{\left(z - 1\right) \left(z + 2\right)^{3}}$$
(1 + z)/((-1 + z)*(2 + z)^3)
Fraction decomposition [src]
-2/(9*(2 + z)^2) - 2/(27*(2 + z)) + 1/(3*(2 + z)^3) + 2/(27*(-1 + z))
$$- \frac{2}{27 \left(z + 2\right)} - \frac{2}{9 \left(z + 2\right)^{2}} + \frac{1}{3 \left(z + 2\right)^{3}} + \frac{2}{27 \left(z - 1\right)}$$
      2            2            1             2     
- ---------- - ---------- + ---------- + -----------
           2   27*(2 + z)            3   27*(-1 + z)
  9*(2 + z)                 3*(2 + z)               
Assemble expression [src]
      1 + z      
-----------------
                3
(-1 + z)*(2 + z) 
$$\frac{z + 1}{\left(z - 1\right) \left(z + 2\right)^{3}}$$
(1 + z)/((-1 + z)*(2 + z)^3)
Combinatorics [src]
      1 + z      
-----------------
                3
(-1 + z)*(2 + z) 
$$\frac{z + 1}{\left(z - 1\right) \left(z + 2\right)^{3}}$$
(1 + z)/((-1 + z)*(2 + z)^3)
Numerical answer [src]
0.125*(1.0 + z)/((1 + 0.5*z)^3*(-1.0 + z))
0.125*(1.0 + z)/((1 + 0.5*z)^3*(-1.0 + z))
Combining rational expressions [src]
      1 + z      
-----------------
                3
(-1 + z)*(2 + z) 
$$\frac{z + 1}{\left(z - 1\right) \left(z + 2\right)^{3}}$$
(1 + z)/((-1 + z)*(2 + z)^3)
Trigonometric part [src]
      1 + z      
-----------------
                3
(-1 + z)*(2 + z) 
$$\frac{z + 1}{\left(z - 1\right) \left(z + 2\right)^{3}}$$
(1 + z)/((-1 + z)*(2 + z)^3)
Rational denominator [src]
      1 + z      
-----------------
                3
(-1 + z)*(2 + z) 
$$\frac{z + 1}{\left(z - 1\right) \left(z + 2\right)^{3}}$$
(1 + z)/((-1 + z)*(2 + z)^3)
Powers [src]
      1 + z      
-----------------
                3
(-1 + z)*(2 + z) 
$$\frac{z + 1}{\left(z - 1\right) \left(z + 2\right)^{3}}$$
(1 + z)/((-1 + z)*(2 + z)^3)
Common denominator [src]
           1 + z           
---------------------------
      4            3      2
-8 + z  - 4*z + 5*z  + 6*z 
$$\frac{z + 1}{z^{4} + 5 z^{3} + 6 z^{2} - 4 z - 8}$$
(1 + z)/(-8 + z^4 - 4*z + 5*z^3 + 6*z^2)