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How do you (x^2+3*x-4)/(x+4) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
 2          
x  + 3*x - 4
------------
   x + 4    
$$\frac{\left(x^{2} + 3 x\right) - 4}{x + 4}$$
(x^2 + 3*x - 4)/(x + 4)
General simplification [src]
-1 + x
$$x - 1$$
-1 + x
Fraction decomposition [src]
-1 + x
$$x - 1$$
-1 + x
Combinatorics [src]
-1 + x
$$x - 1$$
-1 + x
Powers [src]
      2      
-4 + x  + 3*x
-------------
    4 + x    
$$\frac{x^{2} + 3 x - 4}{x + 4}$$
(-4 + x^2 + 3*x)/(4 + x)
Assemble expression [src]
      2      
-4 + x  + 3*x
-------------
    4 + x    
$$\frac{x^{2} + 3 x - 4}{x + 4}$$
(-4 + x^2 + 3*x)/(4 + x)
Trigonometric part [src]
      2      
-4 + x  + 3*x
-------------
    4 + x    
$$\frac{x^{2} + 3 x - 4}{x + 4}$$
(-4 + x^2 + 3*x)/(4 + x)
Combining rational expressions [src]
-4 + x*(3 + x)
--------------
    4 + x     
$$\frac{x \left(x + 3\right) - 4}{x + 4}$$
(-4 + x*(3 + x))/(4 + x)
Numerical answer [src]
(-4.0 + x^2 + 3.0*x)/(4.0 + x)
(-4.0 + x^2 + 3.0*x)/(4.0 + x)
Common denominator [src]
-1 + x
$$x - 1$$
-1 + x
Rational denominator [src]
      2      
-4 + x  + 3*x
-------------
    4 + x    
$$\frac{x^{2} + 3 x - 4}{x + 4}$$
(-4 + x^2 + 3*x)/(4 + x)