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How do you (x^2-25)/(x^2+3*x-40) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
    2        
   x  - 25   
-------------
 2           
x  + 3*x - 40
$$\frac{x^{2} - 25}{\left(x^{2} + 3 x\right) - 40}$$
(x^2 - 25)/(x^2 + 3*x - 40)
Fraction decomposition [src]
1 - 3/(8 + x)
$$1 - \frac{3}{x + 8}$$
      3  
1 - -----
    8 + x
General simplification [src]
5 + x
-----
8 + x
$$\frac{x + 5}{x + 8}$$
(5 + x)/(8 + x)
Rational denominator [src]
          2   
   -25 + x    
--------------
       2      
-40 + x  + 3*x
$$\frac{x^{2} - 25}{x^{2} + 3 x - 40}$$
(-25 + x^2)/(-40 + x^2 + 3*x)
Assemble expression [src]
          2   
   -25 + x    
--------------
       2      
-40 + x  + 3*x
$$\frac{x^{2} - 25}{x^{2} + 3 x - 40}$$
(-25 + x^2)/(-40 + x^2 + 3*x)
Common denominator [src]
      3  
1 - -----
    8 + x
$$1 - \frac{3}{x + 8}$$
1 - 3/(8 + x)
Trigonometric part [src]
          2   
   -25 + x    
--------------
       2      
-40 + x  + 3*x
$$\frac{x^{2} - 25}{x^{2} + 3 x - 40}$$
(-25 + x^2)/(-40 + x^2 + 3*x)
Combinatorics [src]
5 + x
-----
8 + x
$$\frac{x + 5}{x + 8}$$
(5 + x)/(8 + x)
Combining rational expressions [src]
           2   
    -25 + x    
---------------
-40 + x*(3 + x)
$$\frac{x^{2} - 25}{x \left(x + 3\right) - 40}$$
(-25 + x^2)/(-40 + x*(3 + x))
Powers [src]
          2   
   -25 + x    
--------------
       2      
-40 + x  + 3*x
$$\frac{x^{2} - 25}{x^{2} + 3 x - 40}$$
(-25 + x^2)/(-40 + x^2 + 3*x)
Numerical answer [src]
(-25.0 + x^2)/(-40.0 + x^2 + 3.0*x)
(-25.0 + x^2)/(-40.0 + x^2 + 3.0*x)