Mister Exam

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How do you in partial fractions?:
((z^2+1)^2/(4*z^2))/(13+12*((z^2+1)/2*z*z))
x^3*y^12/(x*y^4)^3
2*a*(3*a-p)/(2*p-6*a)
y/(y+3)+y/3+2/y
Factor polynomial:
x^2+x^2
c^2+c^2
x^2-x-y^2-y
c^2-9
Least common denominator:
((z*(a+w))/2)+((w*(a-z))/2)+((a-z)*a)
z-8/z^2/3*z^(1/3)+4
(z-6*z/z+3)/z-3/z+3
(z^5-5*z^3+10*z-10/z+5/z^3-1/z^5)*(z^3-3*z+3/z-1/z^3)
Factor squared:
y^4+9*y^2+2
-y^4-9*y^2+15
-y^4+8*y^2-4
y^4+8*y^2-4
Identical expressions
two *a*(three *a-p)/(two *p- six *a)
2 multiply by a multiply by (3 multiply by a minus p) divide by (2 multiply by p minus 6 multiply by a)
two multiply by a multiply by (three multiply by a minus p) divide by (two multiply by p minus six multiply by a)
2a(3a-p)/(2p-6a)
2a3a-p/2p-6a
2*a*(3*a-p) divide by (2*p-6*a)
Similar expressions
(2*a*(3*a-p))/(2*p-6*a)
2*a*(3*a-p)/(2*p+6*a)
2*a*(3*a+p)/(2*p-6*a)

How do you 2a(3a-p)/(2p-6*a) in partial fractions?

You have entered [src]

2*a*(3*a - p)
-------------
  2*p - 6*a

$$\frac{2 a \left(3 a - p\right)}{- 6 a + 2 p}$$

((2*a)*(3*a - p))/(2*p - 6*a)

Fraction decomposition [src]

-a

$$- a$$

-a

General simplification [src]

-a

$$- a$$

-a

Common denominator [src]

-a

$$- a$$

-a

Combinatorics [src]

-a

$$- a$$

-a

Combining rational expressions [src]

a*(-p + 3*a)
------------
  p - 3*a

$$\frac{a \left(3 a - p\right)}{- 3 a + p}$$

a*(-p + 3*a)/(p - 3*a)

Numerical answer [src]

2.0*a*(-p + 3.0*a)/(2.0*p - 6.0*a)

2.0*a*(-p + 3.0*a)/(2.0*p - 6.0*a)

How do you 2*a*(3*a-p)/(2*p-6*a) in partial fractions?