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How to use it?
How do you in partial fractions?
:
(z^2-4*z+16)/(16*z^2-1)*(4*z^2+z)/(z^3+64)-(z+4)/(4*z^2-z)
z/(2*z-4)-(z^2+4)/(2*z^2-8)-z/(z^2+2*z)
(z-3)/(z+3)*(z+(z^2)/(3-z))
(x^2-4)/(x+2)
Factor polynomial
:
m^5-m^3
x^10-1
x^2-y^2
x^5+y^5+z^5
Least common denominator
:
4*((sin(8*x)/2+4*x)/8-sin(4*x)/2+x)
z/x-z+x+z/z
z/(x+y)+x/(z+y)+y/(z+x)
(z/x*x-3*x)/(z*z/3*x-9)
Factor squared
:
-y^4-y^2+15
-y^4-y^2-11
y^4-9*y^2-3
y^4-y^2-4
Integral of d{x}
:
(x^2-4)/(x+2)
Identical expressions
(x^ two - four)/(x+ two)
(x squared minus 4) divide by (x plus 2)
(x to the power of two minus four) divide by (x plus two)
(x2-4)/(x+2)
x2-4/x+2
(x²-4)/(x+2)
(x to the power of 2-4)/(x+2)
x^2-4/x+2
(x^2-4) divide by (x+2)
Similar expressions
(x^2-4)/(x-2)
(x^2+4)/(x+2)
Expression simplification
/
Fraction Decomposition into the simple
/
(x^2-4)/(x+2)
How do you (x^2-4)/(x+2) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
2 x - 4 ------ x + 2
$$\frac{x^{2} - 4}{x + 2}$$
(x^2 - 4)/(x + 2)
Fraction decomposition
[src]
-2 + x
$$x - 2$$
-2 + x
General simplification
[src]
-2 + x
$$x - 2$$
-2 + x
Common denominator
[src]
-2 + x
$$x - 2$$
-2 + x
Numerical answer
[src]
(-4.0 + x^2)/(2.0 + x)
(-4.0 + x^2)/(2.0 + x)
Combinatorics
[src]
-2 + x
$$x - 2$$
-2 + x