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How to use it?
How do you in partial fractions?
:
1/(x^3+2x^2+x)
x^2/(x^2-1)^4
3/(x^3+5)-9*x^3/(x^3+5)^2
x^2/(x-1)
Factor polynomial
:
z^3+5*z^2+4*z-10
z^3-3*z^2+7*z-5
z^3-1
z^2+z-4
Least common denominator
:
(y/(x-y)+x/(x+y))/(1/x^2+1/y^2)-y^4/(x^2-y^2)
(y/(x*y-x^2)+x/(x*y-y^2))/(x^2+2*x*y+y^2/(1/x+1/y))
y/(4*y+16)+y^2+16/(4*y^2-64)
((y^2-49)/(y^2-14*y+49))^4/((y+7)/(y-7))^4
Factor squared
:
-y^4+8*y^2+2
y^4-8*y^2+12
y^4-9*y^2+7
y^4-8*y^2-4
Integral of d{x}
:
x^2/(x-1)
Graphing y =
:
x^2/(x-1)
Derivative of
:
x^2/(x-1)
Identical expressions
x^ two /(x- one)
x squared divide by (x minus 1)
x to the power of two divide by (x minus one)
x2/(x-1)
x2/x-1
x²/(x-1)
x to the power of 2/(x-1)
x^2/x-1
x^2 divide by (x-1)
Similar expressions
x^2/(x+1)
Expression simplification
/
Fraction Decomposition into the simple
/
x^2/(x-1)
How do you x^2/(x-1) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
2 x ----- x - 1
$$\frac{x^{2}}{x - 1}$$
x^2/(x - 1)
Fraction decomposition
[src]
1 + x + 1/(-1 + x)
$$x + 1 + \frac{1}{x - 1}$$
1 1 + x + ------ -1 + x
Numerical answer
[src]
x^2/(-1.0 + x)
x^2/(-1.0 + x)
Common denominator
[src]
1 1 + x + ------ -1 + x
$$x + 1 + \frac{1}{x - 1}$$
1 + x + 1/(-1 + x)