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How to use it?
How do you in partial fractions?
:
1/(1-x)+(1+x)/(1-x)^2
(4x-1)/(x^2-4x+8)
x^2/(x-1)
exp(-1/(18*log(2)^2))
Factor polynomial
:
z^2+4*z+13
z^2/2-4*z
y^3+1000
x^6+1
Least common denominator
:
(z/b+b/z)/z^2+b^(2/7)*z^(16*b)
(z^2-2*t+2*t1+exp(t1/t)*(2*t-z^2))*(z^2-2*t+2*t2+exp(t2/t)*(2*t-z^2))
(((y-y)/(3*y-3))+(1/(y-1)))/(y+1)/3
(y/(x-y)+x/(x+y))/(1/x^2+1/y^2)-y^4/(x^2-y^2)
Factor squared
:
-y^4+y^2-2
y^4-9*y^2+15
-y^4+8*y^2+8
y^4-8*y^2-4
Integral of d{x}
:
x^2/(x-1)
Graphing y =
:
x^2/(x-1)
Derivative of
:
x^2/(x-1)
Identical expressions
x^ two /(x- one)
x squared divide by (x minus 1)
x to the power of two divide by (x minus one)
x2/(x-1)
x2/x-1
x²/(x-1)
x to the power of 2/(x-1)
x^2/x-1
x^2 divide by (x-1)
Similar expressions
x^2/(x+1)
Expression simplification
/
Fraction Decomposition into the simple
/
x^2/(x-1)
How do you x^2/(x-1) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
2 x ----- x - 1
$$\frac{x^{2}}{x - 1}$$
x^2/(x - 1)
Fraction decomposition
[src]
1 + x + 1/(-1 + x)
$$x + 1 + \frac{1}{x - 1}$$
1 1 + x + ------ -1 + x
Numerical answer
[src]
x^2/(-1.0 + x)
x^2/(-1.0 + x)
Common denominator
[src]
1 1 + x + ------ -1 + x
$$x + 1 + \frac{1}{x - 1}$$
1 + x + 1/(-1 + x)