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Integral of x^2/(x-1) dx
The solution
Detail solution
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Rewrite the integrand:
x−1x2=x+1+x−11
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Integrate term-by-term:
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
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The integral of a constant is the constant times the variable of integration:
∫1dx=x
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Let u=x−1.
Then let du=dx and substitute du:
∫u1du
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The integral of u1 is log(u).
Now substitute u back in:
log(x−1)
The result is: 2x2+x+log(x−1)
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Add the constant of integration:
2x2+x+log(x−1)+constant
The answer is:
2x2+x+log(x−1)+constant
The answer (Indefinite)
[src]
/
|
| 2 2
| x x
| ----- dx = C + x + -- + log(-1 + x)
| x - 1 2
|
/
2x2+2x+log(x−1)
=
−∞−iπ
Use the examples entering the upper and lower limits of integration.