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x^2/(x-1)

What you mean?

Integral of x^2/(x-1) dx

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The solution

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  1         
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01x2x1dx\int\limits_{0}^{1} \frac{x^{2}}{x - 1}\, dx
Integral(x^2/(x - 1*1), (x, 0, 1))
Detail solution
  1. Rewrite the integrand:

    x2x1=x+1+1x1\frac{x^{2}}{x - 1} = x + 1 + \frac{1}{x - 1}

  2. Integrate term-by-term:

    1. The integral of xnx^{n} is xn+1n+1\frac{x^{n + 1}}{n + 1} when n1n \neq -1:

      xdx=x22\int x\, dx = \frac{x^{2}}{2}

    1. The integral of a constant is the constant times the variable of integration:

      1dx=x\int 1\, dx = x

    1. Let u=x1u = x - 1.

      Then let du=dxdu = dx and substitute dudu:

      1udu\int \frac{1}{u}\, du

      1. The integral of 1u\frac{1}{u} is log(u)\log{\left(u \right)}.

      Now substitute uu back in:

      log(x1)\log{\left(x - 1 \right)}

    The result is: x22+x+log(x1)\frac{x^{2}}{2} + x + \log{\left(x - 1 \right)}

  3. Add the constant of integration:

    x22+x+log(x1)+constant\frac{x^{2}}{2} + x + \log{\left(x - 1 \right)}+ \mathrm{constant}


The answer is:

x22+x+log(x1)+constant\frac{x^{2}}{2} + x + \log{\left(x - 1 \right)}+ \mathrm{constant}

The answer (Indefinite) [src]
  /                                   
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 |    2                2              
 |   x                x               
 | ----- dx = C + x + -- + log(-1 + x)
 | x - 1              2               
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x2+2x2+log(x1){{x^2+2\,x}\over{2}}+\log \left(x-1\right)
The answer [src]
-oo - pi*I
%a{\it \%a}
=
=
-oo - pi*I
iπ-\infty - i \pi
Numerical answer [src]
-42.5909567862195
-42.5909567862195

    Use the examples entering the upper and lower limits of integration.