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How to use it?
How do you in partial fractions?
:
(x+1)/(x^3-1)
(4x(x+sqrt(x^2-1)^2))/((x+(sqrtx^2-1))^4-1)
((3*x+2)^4+12*(3*x+2)^3*(x-1))/(3*x-2)^4-12*(3*x+2)^4*(x-1)/(3*x-2)^5
(x^2)/(1+x)
Factor polynomial
:
x^6/2+4*x^3/3
x^5-y^5
x^5-x-x^3
x^5+x-8
Least common denominator
:
x/7+y/7
((u^2-2*u+4)/(4*u^2-1)*(2*u^2+u)/(u^3+8)-(u+2/2*u^2-u))/7/(u^2+2*u)-(10*u+1)/(7-14*u)
-sqrt(91)*sqrt(1/(6+tan(x)*sqrt(364)))*(1+tan(x)^2)/(6+tan(x)*sqrt(364))
sqrt(14)/(7*sqrt(1-2*x^2/7))
Factor squared
:
y^2+4*y*x+10*x^2
-y^2-4*y*b+6*b^2
y^2-4*y*x-3*x^2
-y^2-4*y*x+5*x^2
Integral of d{x}
:
(x^2)/(1+x)
Graphing y =
:
(x^2)/(1+x)
Identical expressions
(x^ two)/(one +x)
(x squared ) divide by (1 plus x)
(x to the power of two) divide by (one plus x)
(x2)/(1+x)
x2/1+x
(x²)/(1+x)
(x to the power of 2)/(1+x)
x^2/1+x
(x^2) divide by (1+x)
Similar expressions
(x^2)/(1-x)
Expression simplification
/
Fraction Decomposition into the simple
/
(x^2)/(1+x)
How do you (x^2)/(1+x) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
2 x ----- 1 + x
$$\frac{x^{2}}{x + 1}$$
x^2/(1 + x)
Fraction decomposition
[src]
-1 + x + 1/(1 + x)
$$x - 1 + \frac{1}{x + 1}$$
1 -1 + x + ----- 1 + x
Numerical answer
[src]
x^2/(1.0 + x)
x^2/(1.0 + x)
Common denominator
[src]
1 -1 + x + ----- 1 + x
$$x - 1 + \frac{1}{x + 1}$$
-1 + x + 1/(1 + x)