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How do you (x^3-27)/(4x^2+12*x+36) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
     3          
    x  - 27     
----------------
   2            
4*x  + 12*x + 36
$$\frac{x^{3} - 27}{\left(4 x^{2} + 12 x\right) + 36}$$
(x^3 - 27)/(4*x^2 + 12*x + 36)
Fraction decomposition [src]
-3/4 + x/4
$$\frac{x}{4} - \frac{3}{4}$$
  3   x
- - + -
  4   4
General simplification [src]
  3   x
- - + -
  4   4
$$\frac{x}{4} - \frac{3}{4}$$
-3/4 + x/4
Common denominator [src]
  3   x
- - + -
  4   4
$$\frac{x}{4} - \frac{3}{4}$$
-3/4 + x/4
Numerical answer [src]
(-27.0 + x^3)/(36.0 + 4.0*x^2 + 12.0*x)
(-27.0 + x^3)/(36.0 + 4.0*x^2 + 12.0*x)
Combining rational expressions [src]
            3    
     -27 + x     
-----------------
4*(9 + x*(3 + x))
$$\frac{x^{3} - 27}{4 \left(x \left(x + 3\right) + 9\right)}$$
(-27 + x^3)/(4*(9 + x*(3 + x)))
Combinatorics [src]
  3   x
- - + -
  4   4
$$\frac{x}{4} - \frac{3}{4}$$
-3/4 + x/4
Rational denominator [src]
           3    
    -27 + x     
----------------
        2       
36 + 4*x  + 12*x
$$\frac{x^{3} - 27}{4 x^{2} + 12 x + 36}$$
(-27 + x^3)/(36 + 4*x^2 + 12*x)
Assemble expression [src]
           3    
    -27 + x     
----------------
        2       
36 + 4*x  + 12*x
$$\frac{x^{3} - 27}{4 x^{2} + 12 x + 36}$$
(-27 + x^3)/(36 + 4*x^2 + 12*x)
Powers [src]
           3    
    -27 + x     
----------------
        2       
36 + 4*x  + 12*x
$$\frac{x^{3} - 27}{4 x^{2} + 12 x + 36}$$
(-27 + x^3)/(36 + 4*x^2 + 12*x)
Trigonometric part [src]
           3    
    -27 + x     
----------------
        2       
36 + 4*x  + 12*x
$$\frac{x^{3} - 27}{4 x^{2} + 12 x + 36}$$
(-27 + x^3)/(36 + 4*x^2 + 12*x)