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How do you x/(2x^2-3x-2) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
      x       
--------------
   2          
2*x  - 3*x - 2
$$\frac{x}{\left(2 x^{2} - 3 x\right) - 2}$$
x/(2*x^2 - 3*x - 2)
Fraction decomposition [src]
1/(5*(1 + 2*x)) + 2/(5*(-2 + x))
$$\frac{1}{5 \left(2 x + 1\right)} + \frac{2}{5 \left(x - 2\right)}$$
     1            2     
----------- + ----------
5*(1 + 2*x)   5*(-2 + x)
General simplification [src]
       x       
---------------
              2
-2 - 3*x + 2*x 
$$\frac{x}{2 x^{2} - 3 x - 2}$$
x/(-2 - 3*x + 2*x^2)
Common denominator [src]
       x       
---------------
              2
-2 - 3*x + 2*x 
$$\frac{x}{2 x^{2} - 3 x - 2}$$
x/(-2 - 3*x + 2*x^2)
Numerical answer [src]
x/(-2.0 + 2.0*x^2 - 3.0*x)
x/(-2.0 + 2.0*x^2 - 3.0*x)
Combining rational expressions [src]
        x        
-----------------
-2 + x*(-3 + 2*x)
$$\frac{x}{x \left(2 x - 3\right) - 2}$$
x/(-2 + x*(-3 + 2*x))
Rational denominator [src]
       x       
---------------
              2
-2 - 3*x + 2*x 
$$\frac{x}{2 x^{2} - 3 x - 2}$$
x/(-2 - 3*x + 2*x^2)
Powers [src]
       x       
---------------
              2
-2 - 3*x + 2*x 
$$\frac{x}{2 x^{2} - 3 x - 2}$$
x/(-2 - 3*x + 2*x^2)
Combinatorics [src]
        x         
------------------
(1 + 2*x)*(-2 + x)
$$\frac{x}{\left(x - 2\right) \left(2 x + 1\right)}$$
x/((1 + 2*x)*(-2 + x))
Trigonometric part [src]
       x       
---------------
              2
-2 - 3*x + 2*x 
$$\frac{x}{2 x^{2} - 3 x - 2}$$
x/(-2 - 3*x + 2*x^2)
Assemble expression [src]
       x       
---------------
              2
-2 - 3*x + 2*x 
$$\frac{x}{2 x^{2} - 3 x - 2}$$
x/(-2 - 3*x + 2*x^2)