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How do you x/(2x^2-x+1) in partial fractions?

You have entered [src]

     x      
------------
   2        
2*x  - x + 1

$$\frac{x}{\left(2 x^{2} - x\right) + 1}$$

x/(2*x^2 - x + 1)

General simplification [src]

     x      
------------
           2
1 - x + 2*x

$$\frac{x}{2 x^{2} - x + 1}$$

x/(1 - x + 2*x^2)

Fraction decomposition [src]

x/(1 - x + 2*x^2)

$$\frac{x}{2 x^{2} - x + 1}$$

     x      
------------
           2
1 - x + 2*x

Numerical answer [src]

x/(1.0 - x + 2.0*x^2)

x/(1.0 - x + 2.0*x^2)

Rational denominator [src]

     x      
------------
           2
1 - x + 2*x

$$\frac{x}{2 x^{2} - x + 1}$$

x/(1 - x + 2*x^2)

Combining rational expressions [src]

       x        
----------------
1 + x*(-1 + 2*x)

$$\frac{x}{x \left(2 x - 1\right) + 1}$$

x/(1 + x*(-1 + 2*x))

Powers [src]

     x      
------------
           2
1 - x + 2*x

$$\frac{x}{2 x^{2} - x + 1}$$

x/(1 - x + 2*x^2)

Combinatorics [src]

     x      
------------
           2
1 - x + 2*x

$$\frac{x}{2 x^{2} - x + 1}$$

x/(1 - x + 2*x^2)

Assemble expression [src]

     x      
------------
           2
1 - x + 2*x

$$\frac{x}{2 x^{2} - x + 1}$$

x/(1 - x + 2*x^2)

Trigonometric part [src]

     x      
------------
           2
1 - x + 2*x

$$\frac{x}{2 x^{2} - x + 1}$$

x/(1 - x + 2*x^2)

Common denominator [src]

     x      
------------
           2
1 - x + 2*x

$$\frac{x}{2 x^{2} - x + 1}$$

x/(1 - x + 2*x^2)