Mister Exam

Lang:

How to use it?
How do you in partial fractions?:
x^2-9/(x+3)^2
(C^2-5c)/(c^2-25)
(9*a^2-16)*(1*(3*a-4)-1/(3*a+4))
(x-6)/(x^2+36)
Factor polynomial:
x^3+y^3+z^3
x^3-8*x^2-23*x+210
x^3-6*x*y+y^3
-x^3+6*x-4*x-8
Least common denominator:
tan((x-pi)/4)-tan((x+pi)/4)
(n*n-2*n)/(n+1)-(n*n-1)/(n+2)
n+6/(4*n+8)-n+2/(4*n-8)+5/(n^2-4)
n+3/(2*n+2)-n+1/(2*n-2)+3/(n^2-1)
Factor squared:
x^2+9*x-6
x^2+5*x+7
-x^2+4*x*y-y^2
-x^2-5*x+14
Identical expressions
(C^ two -5c)/(c^ two - twenty-five)
(C squared minus 5c) divide by (c squared minus 25)
(C to the power of two minus 5c) divide by (c to the power of two minus twenty minus five)
(C2-5c)/(c2-25)
C2-5c/c2-25
(C²-5c)/(c²-25)
(C to the power of 2-5c)/(c to the power of 2-25)
C^2-5c/c^2-25
(C^2-5c) divide by (c^2-25)
Similar expressions
(C^2-5c)/(c^2+25)
(C^2+5c)/(c^2-25)

How do you (C^2-5c)/(c^2-25) in partial fractions?

You have entered [src]

 2      
c  - 5*c
--------
 2      
c  - 25

$$\frac{c^{2} - 5 c}{c^{2} - 25}$$

(c^2 - 5*c)/(c^2 - 25)

Fraction decomposition [src]

1 - 5/(5 + c)

$$1 - \frac{5}{c + 5}$$

      5  
1 - -----
    5 + c

General simplification [src]

  c  
-----
5 + c

$$\frac{c}{c + 5}$$

c/(5 + c)

Combinatorics [src]

  c  
-----
5 + c

$$\frac{c}{c + 5}$$

c/(5 + c)

Numerical answer [src]

(c^2 - 5.0*c)/(-25.0 + c^2)

(c^2 - 5.0*c)/(-25.0 + c^2)

Common denominator [src]

      5  
1 - -----
    5 + c

$$1 - \frac{5}{c + 5}$$

1 - 5/(5 + c)

Combining rational expressions [src]

c*(-5 + c)
----------
        2 
 -25 + c

$$\frac{c \left(c - 5\right)}{c^{2} - 25}$$

c*(-5 + c)/(-25 + c^2)