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How do you 3/(x^3+5)-9*x^3/(x^3+5)^2 in partial fractions?

An expression to simplify:

The solution

You have entered [src]
               3  
  3         9*x   
------ - ---------
 3               2
x  + 5   / 3    \ 
         \x  + 5/ 
$$- \frac{9 x^{3}}{\left(x^{3} + 5\right)^{2}} + \frac{3}{x^{3} + 5}$$
3/(x^3 + 5) - 9*x^3/(x^3 + 5)^2
Fraction decomposition [src]
-6/(5 + x^3) + 45/(5 + x^3)^2
$$- \frac{6}{x^{3} + 5} + \frac{45}{\left(x^{3} + 5\right)^{2}}$$
    6          45   
- ------ + ---------
       3           2
  5 + x    /     3\ 
           \5 + x / 
General simplification [src]
           3   
   15 - 6*x    
---------------
      6       3
25 + x  + 10*x 
$$\frac{15 - 6 x^{3}}{x^{6} + 10 x^{3} + 25}$$
(15 - 6*x^3)/(25 + x^6 + 10*x^3)
Numerical answer [src]
3.0/(5.0 + x^3) - 0.36*x^3/(1 + 0.2*x^3)^2
3.0/(5.0 + x^3) - 0.36*x^3/(1 + 0.2*x^3)^2
Rational denominator [src]
          2                
  /     3\       3 /     3\
3*\5 + x /  - 9*x *\5 + x /
---------------------------
                 3         
         /     3\          
         \5 + x /          
$$\frac{- 9 x^{3} \left(x^{3} + 5\right) + 3 \left(x^{3} + 5\right)^{2}}{\left(x^{3} + 5\right)^{3}}$$
(3*(5 + x^3)^2 - 9*x^3*(5 + x^3))/(5 + x^3)^3
Combining rational expressions [src]
  /       3\
3*\5 - 2*x /
------------
         2  
 /     3\   
 \5 + x /   
$$\frac{3 \left(5 - 2 x^{3}\right)}{\left(x^{3} + 5\right)^{2}}$$
3*(5 - 2*x^3)/(5 + x^3)^2
Combinatorics [src]
   /        3\
-3*\-5 + 2*x /
--------------
          2   
  /     3\    
  \5 + x /    
$$- \frac{3 \left(2 x^{3} - 5\right)}{\left(x^{3} + 5\right)^{2}}$$
-3*(-5 + 2*x^3)/(5 + x^3)^2
Common denominator [src]
  /         3\ 
 -\-15 + 6*x / 
---------------
      6       3
25 + x  + 10*x 
$$- \frac{6 x^{3} - 15}{x^{6} + 10 x^{3} + 25}$$
-(-15 + 6*x^3)/(25 + x^6 + 10*x^3)