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How to use it?
How do you in partial fractions?
:
(9-m^2)/(m^2+3*m)
1/(x^2+1)
(x^2-4*x+3)/(x+2)
1/(x+1)-(x-1)/(x+1)^2
Factor polynomial
:
z^2+5*z-6
z^2-4*z+8
-y+x*y-2*y^2
y*x^2+x*z^2+z*y^2-y*z^2-x*y^2-z*x^2
Least common denominator
:
x+x*(y/1200)+x*(y/1200)*(y/1200)+x*(y/1200)*(y/1200)*(y/1200)
(x-x^3/6+x^5/120-x^7/5040)^3
(x+x^3/3)*log(x)-(x^3+9*x)/9
x-8/x2/x-8/x2+7*x
Factor squared
:
y^4+6*y^2+4
y^4+6*y^2-6
-y^4+5*y^2-12
y^4+6*y^2-2
Derivative of
:
1/(x^2+1)
Graphing y =
:
1/(x^2+1)
Integral of d{x}
:
1/(x^2+1)
Identical expressions
one /(x^ two + one)
1 divide by (x squared plus 1)
one divide by (x to the power of two plus one)
1/(x2+1)
1/x2+1
1/(x²+1)
1/(x to the power of 2+1)
1/x^2+1
1 divide by (x^2+1)
Similar expressions
1/(x^2-1)
Expression simplification
/
Fraction Decomposition into the simple
/
1/(x^2+1)
How do you 1/(x^2+1) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 ------ 2 x + 1
$$\frac{1}{x^{2} + 1}$$
1/(x^2 + 1)
Fraction decomposition
[src]
1/(1 + x^2)
$$\frac{1}{x^{2} + 1}$$
1 ------ 2 1 + x
Numerical answer
[src]
1/(1.0 + x^2)
1/(1.0 + x^2)