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How to use it?
How do you in partial fractions?
:
1/(x^2+1)
(x^2-4*x+3)/(x+2)
tan(2*a)*tan(a)/((tan(2*a)*tan(a)))
((5x+y)/(x-5y)+(5x-y)/(x+5y)):((x^2+y^2)/(x^2-25y^2))
Factor polynomial
:
-y+x*y-2*y^2
y*x^2+x*z^2+z*y^2-y*z^2-x*y^2-z*x^2
y^6+6*y^3*t^2+9*t^4
y^3-y^3
Least common denominator
:
x+x*(y/1200)+x*(y/1200)*(y/1200)+x*(y/1200)*(y/1200)*(y/1200)
(x-x^3/6+x^5/120-x^7/5040)^3
((x^3+6*x^2+11*x+6)/(-6))+((-x^3-9*x^2-26*x-24)/6)
x-(-1/(1-x)^(1/2))*(1+(-1/((1-x))^(1/2))^2)/(-1/(2*(1-x)^(3/2)))
Factor squared
:
y^4+6*y^2-6
-y^4+5*y^2+15
-y^4+5*y^2-12
y^4+6*y^2-2
Derivative of
:
1/(x^2+1)
Graphing y =
:
1/(x^2+1)
Integral of d{x}
:
1/(x^2+1)
Identical expressions
one /(x^ two + one)
1 divide by (x squared plus 1)
one divide by (x to the power of two plus one)
1/(x2+1)
1/x2+1
1/(x²+1)
1/(x to the power of 2+1)
1/x^2+1
1 divide by (x^2+1)
Similar expressions
1/(x^2-1)
Expression simplification
/
Fraction Decomposition into the simple
/
1/(x^2+1)
How do you 1/(x^2+1) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 ------ 2 x + 1
$$\frac{1}{x^{2} + 1}$$
1/(x^2 + 1)
Fraction decomposition
[src]
1/(1 + x^2)
$$\frac{1}{x^{2} + 1}$$
1 ------ 2 1 + x
Numerical answer
[src]
1/(1.0 + x^2)
1/(1.0 + x^2)