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How to use it?
How do you in partial fractions?
:
(9-m^2)/(m^2+3*m)
-2/(x*x^2)
tan(x+pi/8)/2-1/(2*tan(x+pi/8))
(a^2+4*a)/(a^2+8*a+16)
Factor polynomial
:
z^3-2*z^2+2*z-1
z^3-19*z^2/10-z/5+1/10
z^2-z+5
z^2+z-4
Least common denominator
:
(y/5*x-5*x-y)/(y+5*x)
y/(4*y+16)+(y^2+16)/(4*y^2-64)-(4/(y^2-4*y))
((y^2-49)/(y^2-14*y+49))^4/((y+7)/(y-7))^4
x/y-y/x
Factor squared
:
-y^4+9*y^2-13
-y^4-7*y^2-11
y^4+7*y^2-10
-y^4-8*y^2-3
Graphing y =
:
1/(x^2+1)
Derivative of
:
1/(x^2+1)
Integral of d{x}
:
1/(x^2+1)
Identical expressions
one /(x^ two + one)
1 divide by (x squared plus 1)
one divide by (x to the power of two plus one)
1/(x2+1)
1/x2+1
1/(x²+1)
1/(x to the power of 2+1)
1/x^2+1
1 divide by (x^2+1)
Similar expressions
1/(x^2-1)
Expression simplification
/
Fraction Decomposition into the simple
/
1/(x^2+1)
How do you 1/(x^2+1) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 ------ 2 x + 1
$$\frac{1}{x^{2} + 1}$$
1/(x^2 + 1)
Fraction decomposition
[src]
1/(1 + x^2)
$$\frac{1}{x^{2} + 1}$$
1 ------ 2 1 + x
Numerical answer
[src]
1/(1.0 + x^2)
1/(1.0 + x^2)