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How to use it?
How do you in partial fractions?
:
(c^4)^5*c^8/(c^7)^4
1/(2*sqrt(x)*(1+x))
(x^2+x-12)/(x-3)
-625/112+(x^2+1)^2/((x*(x+1)^2))
Factor polynomial
:
z^3-6*z^2+21*z-26
z^3+5*z^2
z^3-4*z^2+14*z-20
z^3/4-2*z^3/9+7*z^3/12
Least common denominator
:
(-y*e/(e+1)+(1-y)*e/((1-1/(e+1))*(e+1)^2))
y/(4*y+16)+(y^2+16)/(4*y^2-64)-(4/(y^2-4*y))
(y-4/(3*y-3)+1/(y-1))/y+1/(3)+2/(y^2-1)
y^2/x^2+y/x
Factor squared
:
-y^4+8*y^2-13
-y^4+9*y^2+6
-y^4+7*y^2+7
-y^4+7*y^2+6
Graphing y =
:
1/(x^2+1)
Derivative of
:
1/(x^2+1)
Integral of d{x}
:
1/(x^2+1)
Identical expressions
one /(x^ two + one)
1 divide by (x squared plus 1)
one divide by (x to the power of two plus one)
1/(x2+1)
1/x2+1
1/(x²+1)
1/(x to the power of 2+1)
1/x^2+1
1 divide by (x^2+1)
Similar expressions
1/(x^2-1)
Expression simplification
/
Fraction Decomposition into the simple
/
1/(x^2+1)
How do you 1/(x^2+1) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 ------ 2 x + 1
$$\frac{1}{x^{2} + 1}$$
1/(x^2 + 1)
Fraction decomposition
[src]
1/(1 + x^2)
$$\frac{1}{x^{2} + 1}$$
1 ------ 2 1 + x
Numerical answer
[src]
1/(1.0 + x^2)
1/(1.0 + x^2)