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How to use it?
How do you in partial fractions?
:
(y/(y-10))-(y^2/(y^2-100))
-1/x+x/(2*x+3)
(x^2+x-12)/(x-3)
1/(x^4+1)
Factor polynomial
:
z^3-5*z^2+9*z-45
z^3-3*z^2+7*z-5
z^3-3*z^2+4*z-2
z^3+3*z^2+4*z+12
Least common denominator
:
y*(y+((1/(x+(x^2+y^2)^(1/2))*(1+(2*x/(2*(x^2+y^2)^(1/2)))))))-(y/(x^2+y^2)^(1/2))
((x/(y-x))^-2)*((x^2+x*y)/(((x+y)^2)+4*x*y))
(x/x+1+1)-x2/4*x2-1
x/3-x/5
Factor squared
:
y^4-9*y^2-9
-y^4+8*y^2+15
y^4-8*y^2+12
y^4-9*y^2+15
Graphing y =
:
1/(x^2+1)
Derivative of
:
1/(x^2+1)
Integral of d{x}
:
1/(x^2+1)
Identical expressions
one /(x^ two + one)
1 divide by (x squared plus 1)
one divide by (x to the power of two plus one)
1/(x2+1)
1/x2+1
1/(x²+1)
1/(x to the power of 2+1)
1/x^2+1
1 divide by (x^2+1)
Similar expressions
1/(x^2-1)
Expression simplification
/
Fraction Decomposition into the simple
/
1/(x^2+1)
How do you 1/(x^2+1) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 ------ 2 x + 1
1
x
2
+
1
\frac{1}{x^{2} + 1}
x
2
+
1
1
1/(x^2 + 1)
Fraction decomposition
[src]
1/(1 + x^2)
1
x
2
+
1
\frac{1}{x^{2} + 1}
x
2
+
1
1
1 ------ 2 1 + x
Numerical answer
[src]
1/(1.0 + x^2)
1/(1.0 + x^2)