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How to use it?
How do you in partial fractions?
:
4tgx(1-tg^2x)/(1+tg^2)^2
x/(x+1)^3
(x-6)/(x^2+36)
((x+3)/(x-1))^2+14(x^2-9)/(x^2-1)-15((x-3)/(x+1))^2
Factor polynomial
:
y^2+5^3
y^2-4*y+4
y^2+12*y+48+64/y
x*y+y^2*x/15+3*x/x+y
Least common denominator
:
(u^2-2*u+4)/(4*u^2-1)*(2*u^2+4)/(u^3+8)
t/(t+3)^3+3/(t+3)^3
tan(x)/x^2+x^(4/5)*(-1-cot(x)^2)-(1+tan(x)^2)/x+4*cot(x)/(5*x^(1/5))
tan(x)^atan(x)*(log(tan(x))/(1+x^2)+(1+tan(x)^2)*atan(x)/tan(x))
Factor squared
:
-y^4+2*y^2+8
-y^4+2*y^2-12
-y^4-2*y^2-10
-y^4-2*y^2+9
Integral of d{x}
:
1/(x^2-2)
Identical expressions
one /(x^ two - two)
1 divide by (x squared minus 2)
one divide by (x to the power of two minus two)
1/(x2-2)
1/x2-2
1/(x²-2)
1/(x to the power of 2-2)
1/x^2-2
1 divide by (x^2-2)
Similar expressions
1/(x^2+2)
Expression simplification
/
Fraction Decomposition into the simple
/
1/(x^2-2)
How do you 1/(x^2-2) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 ------ 2 x - 2
$$\frac{1}{x^{2} - 2}$$
1/(x^2 - 2)
Fraction decomposition
[src]
1/(-2 + x^2)
$$\frac{1}{x^{2} - 2}$$
1 ------- 2 -2 + x
Numerical answer
[src]
1/(-2.0 + x^2)
1/(-2.0 + x^2)