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How to use it?
How do you in partial fractions?
:
x/(x+1)^3
((x^4+3)*(-(x^3*(x^4-3))/((x^4+3)^2)+x^3/(x^4+3)))/(x^4-3)
((x-3)*(x+5))/(x^2-9*x+18)
(x+3)/(x^2-1)
Factor polynomial
:
y^2+x*y+x^2+2*x+2*y
y^2+x^2+4*a^2+1-4*a*x-4*a+2*x+2*a*y
y^2+5^3
y^2-1
Least common denominator
:
((u-v)/(2*u+2*v)+(v^2)/(u^2-v^2)+(u-3*v)/(2*v-2*u))*(3*u^2-3*v^2)/2*v
(u^2-2*u+4)/(4*u^2-1)*(2*u^2+4)/(u^3+8)
t/(t+3)^3+3/(t+3)^3
tan(x)^(sqrt(x))*(log(tan(x))/(2*sqrt(x))+sqrt(x)*(1+tan(x)^2)/tan(x))
Factor squared
:
-y^4+2*y^2-9
-y^4+2*y^2-12
-y^4-2*y^2-10
y^4-15*y^2-1
Integral of d{x}
:
1/(x^2-2)
Identical expressions
one /(x^ two - two)
1 divide by (x squared minus 2)
one divide by (x to the power of two minus two)
1/(x2-2)
1/x2-2
1/(x²-2)
1/(x to the power of 2-2)
1/x^2-2
1 divide by (x^2-2)
Similar expressions
1/(x^2+2)
Expression simplification
/
Fraction Decomposition into the simple
/
1/(x^2-2)
How do you 1/(x^2-2) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 ------ 2 x - 2
$$\frac{1}{x^{2} - 2}$$
1/(x^2 - 2)
Fraction decomposition
[src]
1/(-2 + x^2)
$$\frac{1}{x^{2} - 2}$$
1 ------- 2 -2 + x
Numerical answer
[src]
1/(-2.0 + x^2)
1/(-2.0 + x^2)