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How to use it?
How do you in partial fractions?
:
sqrt((625*x^4+25*10^10*x^2)/(1+25*x^2)^2)
6*(1-4*x^2/(-4+x^2)+4*x^2*(-1+2*x^2/(-4+x^2))/(-4+x^2))/(-4+x^2)^2
sqrt(x)*(-3+5*x^4)+(x^5-3*x)/(2*sqrt(x))
5/(p^3+2*p^2+4*p-2)
Factor polynomial
:
y^2-8*y+29
y^2-4*а+4
y^2-4*y+4
-y^2/4-y/2+11/4
Least common denominator
:
((x+1)*x/2*(2*x+1))+(k+1)^2/((2*k+1)*(2*k+3))
w2/212*a+w-144*a2/212*a+w
v*(1+(-2*x+2*t)/t-(x-t)^2/t^2)/2
(u^2-2*u+4)/(4*u^2-1)*(2*u^2+4)/(u^3+8)
Factor squared
:
-y^4-4*y^2+8
-y^4-3*y^2-3
y^4+3*y^2-11
y^4-3*y^2+12
Integral of d{x}
:
1/(x^2-2)
Identical expressions
one /(x^ two - two)
1 divide by (x squared minus 2)
one divide by (x to the power of two minus two)
1/(x2-2)
1/x2-2
1/(x²-2)
1/(x to the power of 2-2)
1/x^2-2
1 divide by (x^2-2)
Similar expressions
1/(x^2+2)
Expression simplification
/
Fraction Decomposition into the simple
/
1/(x^2-2)
How do you 1/(x^2-2) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 ------ 2 x - 2
$$\frac{1}{x^{2} - 2}$$
1/(x^2 - 2)
Fraction decomposition
[src]
1/(-2 + x^2)
$$\frac{1}{x^{2} - 2}$$
1 ------- 2 -2 + x
Numerical answer
[src]
1/(-2.0 + x^2)
1/(-2.0 + x^2)